It depends on the cross sectional area of the pipe.
2.961 US gallons
12 feet, 6 inches
4*pi = 12.6 cubic feet.
It depends on how long the pool is.
261.66
To calculate the volume of water a water main will hold, we can use the formula for the volume of a cylinder: V = πr²h. First, convert the diameter to radius (18 inches diameter means a radius of 9 inches or 0.75 feet). The length of the water main is 2 miles, which is 10,560 feet. Plugging these values into the formula, we find the volume is approximately 43,500 cubic feet, which is about 326,000 gallons of water.
A 100-foot hose with an inside diameter of five inches can hold 102 US gallons of water.
44.88 gallons
8 cubic feet.
Five feet six inches !
A 100-foot pipe with an inside diameter of 12 inches has a maximum volume of about 78.54 gallons of water.
2.961 US gallons
It depends on how much each pipe can hold. And how long each pipe is.
This container could hold up to 3,949.71 US gallons of water.
12 feet, 6 inches
A cylinder with these dimensions will hold up to 13.06 gallons of water.
Assuming the hose has a 3 in inner diameter; the answer is 50 x 12 x 1.5^2 x pi in cubic inches. Divide the answer by 12 for cubic feet. 4241.15 cubic inches or 353.43 cubic feet.