If your assuming the pool is a perfect cylinder w/ no sloping sides it is easy. (pi/4)*d^2 = V which would be approximately 1810 Ft3. There are 7.4805 Gallons per ft3 which gives us 13,537 gallons. This ofcourse is if u assume your pool is a perfect cylinder. If you have a more accurate messurement i can give you a more specific volume. 13,000 galloons, give or take a couple.
Volume of a cylinder is: Area of the circle x depth Area of a circle is: (pi * diameter^2)/4 where diameter is 2 ft Depth is: 1 ft Therefore, the volume of the cylinder is 3.14ft^2 * 1 ft = 3.14 cubic feet of water
If the sides are straight ... the diameter is 3-ft all the way down ... andthe bottom is flat, then the water is a cylinder.Volume of a cylinder = pi R2 H = pi (1.5)2 (3) = 21.206 cubic feet = 158.6 gallons (rounded)
7,500
261.66
4*pi = 12.6 cubic feet.
Volume of a cylinder is: Area of the circle x depth Area of a circle is: (pi * diameter^2)/4 where diameter is 2 ft Depth is: 1 ft Therefore, the volume of the cylinder is 3.14ft^2 * 1 ft = 3.14 cubic feet of water
If the sides are straight ... the diameter is 3-ft all the way down ... andthe bottom is flat, then the water is a cylinder.Volume of a cylinder = pi R2 H = pi (1.5)2 (3) = 21.206 cubic feet = 158.6 gallons (rounded)
Volume = d2 x h x 0.7854 ~ 7 x7x x 1 x 0.7854 = 49 x 0.7854 = 38.48 Gallons
7,500
What's the depth? This is essential to find cubic feet. Depth x width x length = ? Cubic Feer
261.66
4*pi = 12.6 cubic feet.
The pressure at a depth of 200 feet of water is approximately 86.6 pounds per square inch (psi). This is calculated by dividing the depth (200 feet) by the specific gravity of water (0.433) to determine the pressure in psi.
Roughly 317.5 feet squared.
Diameter x Diamater X Depth X 5.2
You have to know how deep the pool is....and is it a perfect circle? We know the diameter of the pool & therefore the radius & with the aid of Pi we can find the circumference, but without knowing the depth of the water the Q cannot be answered.
It depends on whether the depth changes uniformly along the length of the pool.