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How much water must be added to 300 liters of a solution so that its concentration change from 25 percent to 20 percent?
Wiki User
∙ 12y ago
75 litres
Wiki User
∙ 12y ago
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How many liters of a 90 percent acid solution must be mixed with a 15 percent acid solution to get 600 L of a 80 percent solution?
Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.
How many liters of 10 percent alcohol solution must be mixed with 70 liters of a 70 percent solution to get a 30 percent solution?
210Type your answer here...
How many liters of 93 percent acid solution are needed to make a 9 percent solution with 50 liters of water?
4.84
Pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution How much of the 20 percent solution did the pharmacist use in the mixture?
10
How many liters of 9 percent salt solution and 18 percent salt solution are needed to make 18 liters of 10 percent salt solution?
A. 16 of 18 percent and 2 of 9 percent b. 14 of 18 percent and 4 of 9 percent c. 16 of 9 percent and 2 of 18 percent d. 14 of 9 percent and 4 of 18 percent
How many liters of a 20 percent solution of acid should be added to 10 liters of a 30 percent solution of acid to obtain a 25 percent solution?
10 liters.
How many liters of a 90 percent acid solution must be mixed with a 15 percent acid solution to get 600 L of a 80 percent solution?
Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.
What is the concentration of a solution of 10. moles of copper II nitrate in 5.0 liters of solution?
The concentration of the solution is 2.0 moles per liter. This is calculated by dividing the moles of solute (10. moles) by the volume of the solution in liters (5.0 liters).
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution How much of the 20 percent solution did the pharmacist use in the mixture?
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).
How many liters of 10 percent alcohol solution must be mixed with 70 liters of a 70 percent solution to get a 30 percent solution?
210Type your answer here...
What is the concentration of a solution of 10 moles of copper nitrate in 5.0 liters of solution?
The concentration is 2 M.
What is the percent concentration when 30gms of codeine is dissolved in 2 liters of solution?
The percent concentration of the codeine solution is 1.5%. This is calculated by dividing the mass of codeine (30g) by the total mass of the solution (2000g, since 1 liter of water is approximately 1000g) and then multiplying by 100.
How many liters of 93 percent acid solution are needed to make a 9 percent solution with 50 liters of water?
4.84
A chemist is making 200 L of a solution that is 62 percent acid He is mixing an 80 percent acid solution with a 30 percent acid solution How much of the 80 percent acid solution will he use?
The chemist will use 100 liters of the 80% acid solution and 100 liters of the 30% acid solution to make a 200-liter solution that is 62% acid. The amount of acid in the 80% solution will be 0.8 * 100 = 80 liters, and in the 30% solution, it will be 0.3 * 100 = 30 liters.
How many liters of a 50 percent alcohol solution must be mixed with 40 liters of a 90 percent solution to get a 60 percent solution?
mary mixed 2l of an 80% acid solution with 6l of a 20% acid solution. what was the percent of acid in the resulting mixture
What is the molarity of a solution is defined as?
The concentration in moles of a substance in the solution
How do you find the concenration of a solution?
Concentration of a solution is recorded in molarity (M). Molarity is the moles of solute divided my liters of solution. So to find the concentration of a solution, calculate the number of moles of the solute (the chemical being dissolved) and measure the number of liters of the solution (the water), then divide them.
