To find the volume of a cylindrical water tank, you can use the formula ( V = \pi r^2 h ), where ( r ) is the radius and ( h ) is the height. The diameter is 10 feet, so the radius ( r ) is 5 feet. Plugging in the values, the volume is ( V = \pi (5^2)(20) = \pi (25)(20) = 500\pi ) cubic feet. This is approximately 1570.8 cubic feet, which is the tank's capacity.
Assuming that you're referring to a cylindrical pool that has a 30 foot diameter and is evenly 10 feet deep throughout, it should hold approximately 940 gallons of water.
317.0772
12,345 gallons
261.66
4*pi = 12.6 cubic feet.
Assuming that you're referring to a cylindrical pool that has a 30 foot diameter and is evenly 10 feet deep throughout, it should hold approximately 940 gallons of water.
317.0772
12,345 gallons
im single...txt me 571 262 3132
A cylindrical tank 9 ft in diameter and 100 ft tall will hold ~190,418 gallons.
261.66
4*pi = 12.6 cubic feet.
A cylinder 50 feet in height and 6 inches in diameter can hold up to 73.44 gallons of water.
To determine how much water a 4-foot culvert will hold, you need to know its shape and dimensions. A common cylindrical culvert with a 4-foot diameter will have a volume calculated using the formula for the volume of a cylinder: ( V = \pi r^2 h ), where ( r ) is the radius (2 feet for a 4-foot diameter) and ( h ) is the length of the culvert. For example, if the culvert is 10 feet long, it would hold approximately 125.66 cubic feet of water. To convert this to gallons, multiply by 7.48 (since 1 cubic foot is about 7.48 gallons), resulting in around 941 gallons.
5 foot fish tank holds 566.3 liters. By:Radhika
This wants to know the volume. V=Bh V="pi"r2h V=3.14(10)2(15) V=3.14(100)(15) V=314(15) V=4710ft.3
Do you mean a cylinder with a diameter of 5 feet and length of 12 feet? This would hold about 235.6 cubic feet or 1762.5 gallons