To find the volume of a cylindrical water tank, you can use the formula ( V = \pi r^2 h ), where ( r ) is the radius and ( h ) is the height. The diameter is 10 feet, so the radius ( r ) is 5 feet. Plugging in the values, the volume is ( V = \pi (5^2)(20) = \pi (25)(20) = 500\pi ) cubic feet. This is approximately 1570.8 cubic feet, which is the tank's capacity.
Assuming that you're referring to a cylindrical pool that has a 30 foot diameter and is evenly 10 feet deep throughout, it should hold approximately 940 gallons of water.
317.0772
12,345 gallons
261.66
4*pi = 12.6 cubic feet.
Assuming that you're referring to a cylindrical pool that has a 30 foot diameter and is evenly 10 feet deep throughout, it should hold approximately 940 gallons of water.
317.0772
12,345 gallons
im single...txt me 571 262 3132
A cylindrical tank 9 ft in diameter and 100 ft tall will hold ~190,418 gallons.
261.66
4*pi = 12.6 cubic feet.
A cylinder 50 feet in height and 6 inches in diameter can hold up to 73.44 gallons of water.
5 foot fish tank holds 566.3 liters. By:Radhika
This wants to know the volume. V=Bh V="pi"r2h V=3.14(10)2(15) V=3.14(100)(15) V=314(15) V=4710ft.3
Do you mean a cylinder with a diameter of 5 feet and length of 12 feet? This would hold about 235.6 cubic feet or 1762.5 gallons
The pipe would need to be 10 feet 10.8 inches long.