Work done = Increase in kinetic energy
SO W = (1/2) m (v22 - v12)
So W = 12 x 5 x 3 = 180 J
Kinetic energy of a moving mass is [ 1/2 m V2 .Initial KE of the kart = (1/2) (24) (1)2 = 12 joules.Final KE = (1/2) (24) (4)2 = 192 joules.Difference = amount of energy due to increased speed = (192 - 12) =180 joules.
Kinetic energy of a moving mass is [ 1/2 m V2 ].Initial KE of the kart = (1/2) (24) (1)2 = 12 joulesFinal KE = (1/2) (24) (4)2 = 192 joulesDifference = amount of energy due to increased speed = (192 - 12) = 180 joules.That additional energy had to come from somewhere ... most likely the shopper.A couple of things to notice from this discussion:1). The laws of nature, and Physics in particular, are remarkably constant. That's why the answerto this question, and the method of solution, are identical to the the answer given when the samequestion was submitted two days ago.2). The cart's final speed, 4 meters/sec, is about 8.9 mph, which is a shopping cart careeningdown the canned-vegetable aisle at 6min42sec per mile. I couldn't even do that in high-schoolcross-country. Look out shoppers !
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
30 J
375 Js (((((((((((: this is the right answer
Probably less then solving this question or since F=ma 72N. The N stands for Nitwick.
D. 750 j
Probably less then solving this question or since F=ma 72N. The N stands for Nitwick.
The work done on the shopping cart by the force is equal to the increase in its kinetic energy. Therefore, the work done is 12mv^2. If the force is exerted over a distance d, then the work done is also equal to Fd. Setting these two expressions equal gives you the relationship between the force, distance, and kinetic energy of the shopping cart.
When you are done with your Shopping Cart, you can return it to the store, leave it in a Shopping Cart Corral, or a Shopping Cart Area, which usually says "Please return Shopping Carts Here!" Thank You or it may say " Please help keep costs low by returning your Shopping Cart Here! Thank You". If there are no cart corrals or such things like that in the parking lot, then leave it in the parking lot, just find a spot where a cart will fit, without damages any cars. Do Not Take Shopping Carts Off Store Premises!! It's the Law!!
There are several things that can be done after adding an item to the Paypal shopping cart. One has the option to continue shopping for additional merchandise, continue to checkout and complete the purchase, or save the item in the cart to purchase at a later time.
750 j
1200w 100w
The work done pushing the shopping cart would be 8800 Joules, calculated as force (88N) times distance (100m). Work is the product of force applied in the direction of motion and the distance over which it is applied.
answer: probably not as most supermarkets have signs saying they are not responsible for damage done to cars. You park at your risk. Besides, the fault is not that of the supermarket but of the person who didn't replace the cart.
The work done on the shopping cart is 1000 joules (200 N * 5 m). Work is calculated by multiplying the force applied with the distance the force is applied over.
it means either you bought it or its "added to your shopping cart" as they say. No!! it means it is ready to ship but they havent done it yet