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How much work must be done on a 24 kg shopping cart to increase its speed from 1 m s to 4 m s?
Wiki User
∙ 13y ago
Kinetic energy of a moving mass is [ 1/2 m V2 .
Initial KE of the kart = (1/2) (24) (1)2 = 12 joules.
Final KE = (1/2) (24) (4)2 = 192 joules.
Difference = amount of energy due to increased speed = (192 - 12) =
180 joules.
Wiki User
∙ 13y ago
Makenzie Henthorn
180 J ( apex )
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How much work must be done on a 24 kg shopping cart to increase its speed from 1 ms to 4ms?
Work done = Increase in kinetic energy SO W = (1/2) m (v22 - v12) So W = 12 x 5 x 3 = 180 J
How much work must be done on a 24 kg shopping cart to increase its speed from 1 m's to 4 m's?
Kinetic energy of a moving mass is [ 1/2 m V2 ].Initial KE of the kart = (1/2) (24) (1)2 = 12 joulesFinal KE = (1/2) (24) (4)2 = 192 joulesDifference = amount of energy due to increased speed = (192 - 12) = 180 joules.That additional energy had to come from somewhere ... most likely the shopper.A couple of things to notice from this discussion:1). The laws of nature, and Physics in particular, are remarkably constant. That's why the answerto this question, and the method of solution, are identical to the the answer given when the samequestion was submitted two days ago.2). The cart's final speed, 4 meters/sec, is about 8.9 mph, which is a shopping cart careeningdown the canned-vegetable aisle at 6min42sec per mile. I couldn't even do that in high-schoolcross-country. Look out shoppers !
How much work must be done on a 10kg bicycle to increase its speed from 2 M's to 3 M's?
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
How much work must be done on a 5-kg snowboard to increase its speed from 2 m s to 4 m s?
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How much work must be done on a 10-kg bicycle to increase its speed from 5 m s to 10 m s?
375 Js (((((((((((: this is the right answer
How much work must be done on a 24kg shopping cart to increase its speed from 1 ms to 4 ms?
D. 750 j
How much work must be done on a kg shopping cart to increase its speed from 1 ms to 4 ms?
Probably less then solving this question or since F=ma 72N. The N stands for Nitwick.
How much work must be done on a 24-kg shopping cart to increase its speed from 1 ms to 4 ms?
Probably less then solving this question or since F=ma 72N. The N stands for Nitwick.
How much work must be done on a 24 kg shopping cart to increase its speed from 1 ms to 4ms?
Work done = Increase in kinetic energy SO W = (1/2) m (v22 - v12) So W = 12 x 5 x 3 = 180 J
Where do shopping carts go in a parking lot?
When you are done with your Shopping Cart, you can return it to the store, leave it in a Shopping Cart Corral, or a Shopping Cart Area, which usually says "Please return Shopping Carts Here!" Thank You or it may say " Please help keep costs low by returning your Shopping Cart Here! Thank You". If there are no cart corrals or such things like that in the parking lot, then leave it in the parking lot, just find a spot where a cart will fit, without damages any cars. Do Not Take Shopping Carts Off Store Premises!! It's the Law!!
What options are available after adding an item to the Paypal shopping cart?
There are several things that can be done after adding an item to the Paypal shopping cart. One has the option to continue shopping for additional merchandise, continue to checkout and complete the purchase, or save the item in the cart to purchase at a later time.
How much work must be done on a 20-kg go-cart to increase its speed from 5 m/s to 10 m/s?
750 j
What is the supermarket liability if a shopping cart strikes your vehicle?
answer: probably not as most supermarkets have signs saying they are not responsible for damage done to cars. You park at your risk. Besides, the fault is not that of the supermarket but of the person who didn't replace the cart.
What does Item accepted mean while ordering online?
it means either you bought it or its "added to your shopping cart" as they say. No!! it means it is ready to ship but they havent done it yet
Why do people take shopping carts outside of store parking lots?
So if they have to much stuff to carry then they have a shopping cart to take to their car and put all the stuff inside that they buy but then have have to put the shopping cart away when they are done with it. That answer is why people take if out side the store. However, the question asked, why do customers, take the carts of the parking lots, and most of the time it is because they walk home, and don't want to carry the goods.
What would be done to increase the compressor speed on a belt-driven compressor?
increase drive pulley size
How much work must be done on a 24 kg shopping cart to increase its speed from 1 m's to 4 m's?
Kinetic energy of a moving mass is [ 1/2 m V2 ].Initial KE of the kart = (1/2) (24) (1)2 = 12 joulesFinal KE = (1/2) (24) (4)2 = 192 joulesDifference = amount of energy due to increased speed = (192 - 12) = 180 joules.That additional energy had to come from somewhere ... most likely the shopper.A couple of things to notice from this discussion:1). The laws of nature, and Physics in particular, are remarkably constant. That's why the answerto this question, and the method of solution, are identical to the the answer given when the samequestion was submitted two days ago.2). The cart's final speed, 4 meters/sec, is about 8.9 mph, which is a shopping cart careeningdown the canned-vegetable aisle at 6min42sec per mile. I couldn't even do that in high-schoolcross-country. Look out shoppers !
