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How much work must be done on a 5-kg snowboard to increase its speed from 2 m s to 4 m s?
Wiki User
∙ 14y ago
30 J
Wiki User
∙ 14y ago
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How much work must be done on a 10-kg bicycle to increase its speed from 5 m s to 10 m s?
375 Js (((((((((((: this is the right answer
How much work must be done on a 10kg bicycle to increase its speed from 2 M's to 3 M's?
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
How much work must be done on a 24 kg shopping cart to increase its speed from 1 ms to 4ms?
Work done = Increase in kinetic energy SO W = (1/2) m (v22 - v12) So W = 12 x 5 x 3 = 180 J
She ran 300 meters in 30 seconds how much did her speed increase?
Her average speed was 10 m/s. You probably missed something in the question, there isn't enough there to determine "how much it increased by".
How much work has to be done on a 5 kg sled to increase its speed from 10 m s to 15 m s?
Work is simply a transfer of energy. Calculate the kinetic energy for both speeds, then calculate the difference. The formula for kinetic energy is KE = (1/2)mv2. If the mass is in kilograms, and the velocity (or speed) is in meter/second, the energy is in Joule.
How much work must be done on a 10-kg snowboard to increase its speed from 2ms to 4 ms 100 J.?
The work done on the snowboard to increase its speed is 100 Joules. This work-energy theorem is based on the change in kinetic energy, given by the equation: work = change in kinetic energy. In this case, the snowboard has a mass of 10 kg and the speed increases from 2 m/s to 4 m/s.
How much work must be done on a 5kg snowborad to increase its speed from 2ms to 4ms?
The work done on the snowboard can be calculated using the work-energy theorem. The work done is equal to the change in kinetic energy of the snowboard. Given the mass of 5kg and initial and final speeds of 2m/s and 4m/s respectively, the work done on the snowboard is 100 Joules.
How much work must be done on a 5 kg snowboard to increase its speed from 2 ms to 4 ms?
The work done on the snowboard is calculated as the change in kinetic energy. The formula for kinetic energy is KE = 0.5 * mass * velocity^2. By calculating the initial and final kinetic energies, the work done would be the difference between the two. In this case, the work done on the snowboard is 60J.
How much work must be done on a 10-kg snowboard to increase its speed from 4 ms to 6 ms?
225000 J
How much work must be done on a 10-kg snowboard to increase its speed from 4 ms to 6 ms 100 J.?
The work done on the snowboard is equal to the change in kinetic energy. The initial kinetic energy is (1/2)mv^2 = (1/2)(10 kg)(4 m/s)^2 = 80 J. The final kinetic energy is (1/2)(10 kg)(6 m/s)^2 = 180 J. Therefore, the work done is 180 J - 80 J = 100 J.
How much work must be done on a kg sled to increase its speed from 10ms to 15 ms?
To calculate the work done on the sled to increase its speed, you need to know the initial and final kinetic energy. The work done is equal to the change in kinetic energy, which is given by the formula: Work = (1/2) * m * (vf^2 - vi^2) Substitute the mass of the sled, initial speed, and final speed to find the work done.
How much work must be done on a 10-kg snowboard to increase its speed from 2 ms to 4 ms?
The work done is equal to the change in kinetic energy of the snowboard. The formula for kinetic energy is KE = 0.5 * mass * velocity^2. The initial kinetic energy is KE_initial = 0.5 * 10 kg * (2 m/s)^2 = 20 J, and the final kinetic energy is KE_final = 0.5 * 10 kg * (4 m/s)^2 = 80 J. The work done is the difference: Work = KE_final - KE_initial = 80 J - 20 J = 60 J.
How much work is done to increase a 20 kg scooters speed from 10 ms to 20 ms?
3000j
How much work must be done on a 5-kg sled to increase its speed from 10 m/s to 15 m/s?
312.5 J
How much is a ride snowboard worth?
You can look for a cheaper ride snowboard in online shops
How much work is done to increase a 20-kg scooter's speed from 10 m/s to 20 m/s?
3000 J *Shelby Sarah*
How much work must be done on a 20-kg go-cart to increase its speed from 5 m/s to 10 m/s?
750 j
