Simple interest or compound interest?
If simple --- I = prt
= 300,000 x .05 x 12
total amount = I +p = answer above + 300,000
if compounded annually, P(t) = p((1+r)t)
= 300,000 x ((1.05)12) this is total amount
It depends on when it's compounded. Left alone and compounded annually, the total is 441.87.
The total grows as time passes. That's the whole idea of interest and compounding. In order to calculate what the total is now, we need to know how long it has been in the account accumulating interest, and you haven't told us that.
Total = 144000(1+i)n Total = 144000(1.340095640625) Total = 192973.77225
If every six months the capital earn 10% interest which is compounded, at the end of 5 years, the interest will be 31875. If the annual interest rate is 10%, it makes no difference how often it is compounded. The six monthly interest rate is adjusted - to 4.88% rather than 5% - so that the total interest for a year is 10%.
Total = 1000(1+0.06)4 = 1262.48
It depends on when it's compounded. Left alone and compounded annually, the total is 441.87.
The total grows as time passes. That's the whole idea of interest and compounding. In order to calculate what the total is now, we need to know how long it has been in the account accumulating interest, and you haven't told us that.
Total = 144000(1+i)n Total = 144000(1.340095640625) Total = 192973.77225
If every six months the capital earn 10% interest which is compounded, at the end of 5 years, the interest will be 31875. If the annual interest rate is 10%, it makes no difference how often it is compounded. The six monthly interest rate is adjusted - to 4.88% rather than 5% - so that the total interest for a year is 10%.
$44,440.71
No. Assets = Liabilities + Owner's Equity = 300,000 + 300,000 = 600,000
Total = 1000(1+0.06)4 = 1262.48
The total interest will be 1160.53 units of currency.
To calculate the total amount Wallace will pay on a $5,000 loan with a 4% annual interest rate compounded annually over six years, we use the formula for compound interest: ( A = P(1 + r)^n ), where ( A ) is the total amount, ( P ) is the principal amount ($5,000), ( r ) is the annual interest rate (0.04), and ( n ) is the number of years (6). Plugging in the values: [ A = 5000(1 + 0.04)^6 = 5000(1.265319) \approx 6326.59 ] Therefore, Wallace will pay approximately $6,326.59 in total.
500 principal, 10 percent annual rate => 50 annual interest 2 year => 100 total interest.
15,000*0.0425*5/12 = 265.625 unless it is compounded on a daily basis.
Total value = 20000*(1.06)2 = 22472 So interest = 2472