sin[squared]60 is the same as (sin 60)^2 or (sin 60)*(sin 60)
If you dont know the sines and cosines of a 30-60-90 triangle off the top of your head, you can enter into a calculator to find out.
sin 60 = 3^(1/2)/2 OR "The square root of three divided by two"
cos 30 = 3^(1/2)/2 OR " ' ' ' ' ' ' ' ' "
So we end up with:
[ 3^(1/2) / 2 ]^2 + [ 3^(1/2) / 2 ]^2
Since it's the same thing twice, we can say:
2 * [ 3^(1/2) / 2 ]^2
Squaring...
2 * [ 3^(1/2) / 2 ] * [ 3^(1/2) / 2 ]
2 * [ 3 / 4]
[ 6 / 4 ] = 1.5
chandan
urs...........
Perhaps you can ask the angel to shed some divine light on the question! Suppose the base is BC, with angle B = 75 degrees angle C = 30 degrees then that angle A = 180 - (75+30) = 75 degrees. Suppose the side opposite angle A is of length a mm, the side opposite angle B is b mm and the side opposite angle C is c mm. Then by the sine rule a/sin(A) = b/(sin(B) = c/sin(C) This gives b = a*sin(B)/sin(A) and c = a*sin(C)/sin(A) Therefore, perimeter = 150 mm = a+b+c = a/sin(A) + a*sin(B)/sin(A) + a*sin(C)/sin(A) so 150 = a*{1/sin(A) + sin(B)/sin(A) + sin(C)/sin(A)} or 150 = a{x} where every term for x is known. This equation can be solved for a. So draw the base of length a. At one end, draw an angle of 75 degrees, at the other one of 30 degrees and that is it!
If its a 300-600-right angle triangle then the third angle must be 90 degrees. Then its base squared plus its height squared equals its hypotenuse squared usually written in the form of: a2+b2 = c2
if r = perpendicular distance center of hexagon to a side, and r^2 = r squared, then AREA = 6x r^2 x tan 30 degrees = 3.464 r^2 or if R = distance center of hexagon to a corner, AREA = 3 R^2 sin 60 = 2.598 R^2
5.477225575 squared equals 30.
The trigonometric function of an angle gives a certain value The arc trigonometric function of value is simply the angle For example, if sin (30 degrees) = 0.500 then arc sine ( 0.500) = 30 degrees
cos(30) = sqrt(3)/2 so cosine squared is 3/4.
Sin theta of 30 degrees is1/2
SQRT(3)/4 - 1/4
sin(360+30) =sin(30)= 1/2
Sin30 degrees is 0.50000
sin(30) = 0.5
Perhaps you can ask the angel to shed some divine light on the question! Suppose the base is BC, with angle B = 75 degrees angle C = 30 degrees then that angle A = 180 - (75+30) = 75 degrees. Suppose the side opposite angle A is of length a mm, the side opposite angle B is b mm and the side opposite angle C is c mm. Then by the sine rule a/sin(A) = b/(sin(B) = c/sin(C) This gives b = a*sin(B)/sin(A) and c = a*sin(C)/sin(A) Therefore, perimeter = 150 mm = a+b+c = a/sin(A) + a*sin(B)/sin(A) + a*sin(C)/sin(A) so 150 = a*{1/sin(A) + sin(B)/sin(A) + sin(C)/sin(A)} or 150 = a{x} where every term for x is known. This equation can be solved for a. So draw the base of length a. At one end, draw an angle of 75 degrees, at the other one of 30 degrees and that is it!
The angle of refraction can be calculated using Snell's Law: n1sin(theta1) = n2sin(theta2), where n1 and n2 are the refractive indices of the media, and theta1 and theta2 are the angles of incidence and refraction, respectively. Given n1 = 1.33, n2 = 1 (since in air), and theta1 = 30 degrees, we can solve for theta2 to find it is approximately 22.62 degrees.
If tan 3a is equal to sin cos 45 plus sin 30, then the value of a = 0.4.
Instead of alpha and beta for the angles, I will use A and B. Firstly, I would find the second side, b, using the sin rule which states: a/sinA = b/sinB So 27/sin(30°20') = b/sin(50°10') ==> b = 27*sin(50°10')/sin(30°20') where * means multiply ==> b = 27*0.7679/0.5050 = 41.0542 Then find the 3rd angle, C remembering the sum of the angles in a triangle is 180° C = 180 - 50°10' - 30°20' = 99° 30' Now to find the area, use the formula: Area = 1/2 * a * b * sin C ==> 1/2 * 27 * 41.0542 * sin(99°30') = 546.6308 sq cm.
You can if you know the lengths of the two pairs of sides. Thanks to the fact that sin(30) = 0.5, the height of the parallelogram is half the length of the sloping side.
If its a 300-600-right angle triangle then the third angle must be 90 degrees. Then its base squared plus its height squared equals its hypotenuse squared usually written in the form of: a2+b2 = c2