sin[squared]60 is the same as (sin 60)^2 or (sin 60)*(sin 60)
If you dont know the sines and cosines of a 30-60-90 triangle off the top of your head, you can enter into a calculator to find out.
sin 60 = 3^(1/2)/2 OR "The square root of three divided by two"
cos 30 = 3^(1/2)/2 OR " ' ' ' ' ' ' ' ' "
So we end up with:
[ 3^(1/2) / 2 ]^2 + [ 3^(1/2) / 2 ]^2
Since it's the same thing twice, we can say:
2 * [ 3^(1/2) / 2 ]^2
Squaring...
2 * [ 3^(1/2) / 2 ] * [ 3^(1/2) / 2 ]
2 * [ 3 / 4]
[ 6 / 4 ] = 1.5
chandan
urs...........
Perhaps you can ask the angel to shed some divine light on the question! Suppose the base is BC, with angle B = 75 degrees angle C = 30 degrees then that angle A = 180 - (75+30) = 75 degrees. Suppose the side opposite angle A is of length a mm, the side opposite angle B is b mm and the side opposite angle C is c mm. Then by the sine rule a/sin(A) = b/(sin(B) = c/sin(C) This gives b = a*sin(B)/sin(A) and c = a*sin(C)/sin(A) Therefore, perimeter = 150 mm = a+b+c = a/sin(A) + a*sin(B)/sin(A) + a*sin(C)/sin(A) so 150 = a*{1/sin(A) + sin(B)/sin(A) + sin(C)/sin(A)} or 150 = a{x} where every term for x is known. This equation can be solved for a. So draw the base of length a. At one end, draw an angle of 75 degrees, at the other one of 30 degrees and that is it!
If its a 300-600-right angle triangle then the third angle must be 90 degrees. Then its base squared plus its height squared equals its hypotenuse squared usually written in the form of: a2+b2 = c2
if r = perpendicular distance center of hexagon to a side, and r^2 = r squared, then AREA = 6x r^2 x tan 30 degrees = 3.464 r^2 or if R = distance center of hexagon to a corner, AREA = 3 R^2 sin 60 = 2.598 R^2
5.477225575 squared equals 30.
The trigonometric function of an angle gives a certain value The arc trigonometric function of value is simply the angle For example, if sin (30 degrees) = 0.500 then arc sine ( 0.500) = 30 degrees
cos(30) = sqrt(3)/2 so cosine squared is 3/4.
Sin theta of 30 degrees is1/2
SQRT(3)/4 - 1/4
sin(360+30) =sin(30)= 1/2
Sine(30) = 0.5 or 1/2
sin(30) = 0.5
Perhaps you can ask the angel to shed some divine light on the question! Suppose the base is BC, with angle B = 75 degrees angle C = 30 degrees then that angle A = 180 - (75+30) = 75 degrees. Suppose the side opposite angle A is of length a mm, the side opposite angle B is b mm and the side opposite angle C is c mm. Then by the sine rule a/sin(A) = b/(sin(B) = c/sin(C) This gives b = a*sin(B)/sin(A) and c = a*sin(C)/sin(A) Therefore, perimeter = 150 mm = a+b+c = a/sin(A) + a*sin(B)/sin(A) + a*sin(C)/sin(A) so 150 = a*{1/sin(A) + sin(B)/sin(A) + sin(C)/sin(A)} or 150 = a{x} where every term for x is known. This equation can be solved for a. So draw the base of length a. At one end, draw an angle of 75 degrees, at the other one of 30 degrees and that is it!
The sine of 210 degrees is equal to -1/2. This value can be derived from the unit circle, where 210 degrees is in the third quadrant, where sine values are negative. Specifically, sin(210°) corresponds to sin(210° - 180°) = sin(30°), and since sine is negative in the third quadrant, sin(210°) = -sin(30°) = -1/2.
First make sure your calculator is in 'Degree Mode (D)'. Then using the 'Inverse' of 'Sin' , shown as 'ArcSin' or ' Sin^(-1)' . enter '0.5', followed by '=' . The answer should be '30' ( 30 degrees).
nwater * sin 30=nair *sin(angle of refraction) 1.33*0.5=1*sin(angle of refraction) sin(angle of refractiob)=0.665 angle of refraction inair=41.6 degrees nwater * sin 30=nair *sin(angle of refraction) 1.33*0.5=1*sin(angle of refraction) sin(angle of refractiob)=0.665 angle of refraction inair=41.6 degrees
4Sin(theta) = 2 Sin(Theta) = 2/4 = 1/2 - 0.5 Theta = Sin^(-1) [0.5] Theta = 30 degrees.
If tan 3a is equal to sin cos 45 plus sin 30, then the value of a = 0.4.