Well, honey, to prove that the equation tan z = z has only real roots, you gotta show that the function f(z) = tan z - z has no zeros with nonzero imaginary parts. One way to do that is by analyzing the behavior of f(z) on the real line and using the Intermediate Value Theorem. So, put on your thinking cap and get ready to dive into some complex analysis, darling.
normally an equation with the x value squared there would be two roots. the two roots are positive 1 and postitive 1. since they are they same number there is actually only one root.
Without an "equals" somewhere along the way, you only have an expression, not an equation.Without an equation, there is no question, and nothing to answer.
Factors are (x - 1)(x - 1) so only one root.
In the absence of a proper statement of the equation I can only guess at answers. How about (2x + 3)(3x - 5) which is the factorisation of 6x2 - x - 15 = 0? In which case x = -2/3 or 5/3.
The equation ax^2 + bx + c = 0 where a, b and c are real and a is non-zero has discriminant D = b^2 – 4ac. Then,if D > 0 the equation has two real roots which are distinct;if D = 0 the equation has two real roots which are coincident;if D < 0 the equation has two roots which form a complex conjugate pair (advanced mathematics only).
normally an equation with the x value squared there would be two roots. the two roots are positive 1 and postitive 1. since they are they same number there is actually only one root.
Without an "equals" somewhere along the way, you only have an expression, not an equation.Without an equation, there is no question, and nothing to answer.
Factors are (x - 1)(x - 1) so only one root.
In the absence of a proper statement of the equation I can only guess at answers. How about (2x + 3)(3x - 5) which is the factorisation of 6x2 - x - 15 = 0? In which case x = -2/3 or 5/3.
The equation ax^2 + bx + c = 0 where a, b and c are real and a is non-zero has discriminant D = b^2 – 4ac. Then,if D > 0 the equation has two real roots which are distinct;if D = 0 the equation has two real roots which are coincident;if D < 0 the equation has two roots which form a complex conjugate pair (advanced mathematics only).
Write the quadratic equation in the form ax2 + bx + c = 0 The roots are equal if and only if b2 - 4ac = 0. The expression, b2-4ac is called the [quadratic] discriminant.
The equation contains variables which are only raised to the first power.
You can't prove it, because it's usually not true.The only time it's true is when x=0 .
This equation is unsolvable since there are two unknowns and only one equation. You would require a second equation in order to solve it.
-4
There is only one equation that is given in the question and that equation is not a direct variation.
A discriminant is based on the differences between roots of an equation. A linear equation, such as the onle in the question, has only one root and therefore cannot have a discriminant.