The equation ax^2 + bx + c = 0 where a, b and c are real and a is non-zero has discriminant D = b^2 – 4ac. Then,
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The original equation, ax2 + bx + c = 0 has two equal roots whose value is -b/2a.
If the quadratic equation is ax2 + bx + c = 0 then if the discriminant, b2 - 4ac is greater than 0: there are two real roots = [-b + or - sqrt(b2 - 4ac)]/2a equal to 0: there are two real coincidental roots, with the value -b/2a less than 0: there are two complex roots = [-b + or - i*sqrt(b2 - 4ac)]/2a where i is the imaginary square root of -1. The answer to the third case (discr<0) may be given as "there are no real roots".
b2 - 4ac72 - 4(1)(8)49 - 32= 17---------this tells us, by being positive, that there are two real roots in this quadratic .
Oh, dude, that's like the quadratic formula, you know? It's the one where you gotta plug in those numbers and hope for the best. So, yeah, b squared minus 4ac is just a fancy way of saying "let's find those roots, man."
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