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How do you obtain moment generating function Log-normal distribution?
You cannot because it does not exist.Although all the moments of the lognormal distribution do exist, the distribution is not uniquely determined by its moments. One of the consequences of this is that the expected values E[e^tX] does not converge for any positive t.
How do you put log functions in a TI-84?
In order to find the log with a power of ten, use the LOG button. For example, to find log105, type log(5). (The parenthesis after the g will appear when you press the LOG button. In order to find a log with a power other than ten, you will have to divide by the log10 of that power. For example, to find log82, type log(8)/log(2). In order to find the natural log of a number, use the LN key. For example, to find the natural log of 91, type ln(91).
Basic rules to find log and anti log?
no
How can you find value of logarithm from log table?
determination of log table value
What is the minimum number of guesses needed to find a specific number if you are given the hint higher or lower for each guess you make?
Assuming that you want to discount luck (if not, the answer would be 1), and that the guesser always guesses the median of the remaining range, the answer would be the (ceiling of the log(base 2) of the count of numbers in the range). If the log(base 2) is an exact integer, add 1. Example 1, pick a number between 1 and 9. There are 9 numbers in the range, so the log(base2) of 9 is ~3.16. The ceiling of that is 4. Do not add 1 for a final answer of 4. The full range is 1,2,3,4,5,6,7,8,9. The median is 5 First guess is 5. Higher - 6,7,8,9 is remaining range. 7 and 8 are the median numbers Second Guess is 8. Lower - 6,7 is the remaining range. 6 and 7 are the median numbers. Third guess is 7. Lower - 6 is the remaining range. 6 is the median number Fourth guess is 6. Correct. Example 2, pick a number between 1 and 16. There are 16 numbers in the range, so the log(base 2) of 16 is 4. The ceiling of 4 is 4. Add the 1 because the Log(base 2) is an integer, for a final answer of 5. Full range is 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16. The median numbers are 8 and 9. First Guess is 9. Lower - 1,2,3,4,5,6,7,8 is the remaining range. 4 and 5 are the median numbers Second Guess is 4. Higher - 5,6,7,8 is the remaining range. 6 and 7 are the median numbers. Third Guess is 6. Higher - 7,8 is the remaining range. 7 and 8 are the median numbers. Fourth Guess is 7. Higher - 8 is the remaining range. 8 is the median. Fifth guess is 8. Correct Both of these examples show worst case scenarios. A "lucky guess" will reduce the number of guess needed, possibly all the way to 1. Note: I do realize that to a math purist, in the examples where I said that the median numbers were x and y, the correct answer is that the median number is between x and y. Since I can not guess the number between the two numbers, I am bending the definition of median to treat the two bordering numbers as the median when the strict definition would list the median as being between those two numbers.
