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How do you find the average of n numbers?
The average of n numbers = (sum of n numbers) / (count of n numbers).
What are mixed numbers greater than 10 but less than 11?
10m/n for any pair of counting numbers m and n such that m < n
Find the mean of n natural numbers?
Mean = (sum of the n numbers)/n
How can you find the total of the n numbers in a distribution if you know their mean?
Mean = Total of the numbers / n So total of the numbers = n*mean
How do you find the mean of first n natural numbers?
The sum of the first n natural numbers is n*(n+1)/2 There are n numbers so their mean = (n+1)/2
What is the sum of 27 and a number n?
To find the sum of the numbers, we must first know the value of n. This was not included in your question.
How do you find the average of n numbers?
The average of n numbers = (sum of n numbers) / (count of n numbers).
What are mixed numbers greater than 10 but less than 11?
10m/n for any pair of counting numbers m and n such that m < n
Find the mean of n natural numbers?
Mean = (sum of the n numbers)/n
The number 96 can be written as 2m times n where m and n are prime numbers find the value of m and n?
m -5 n-3
How do you find factorial 5 in C programming?
to find the factorial we declare a variable n and initialize its value to 1 initiate a loop for example a for loop and multiply the numbers upto 5 code:- for(i=1,n=1;i<=5;i++) { n=n*i; }
How do you find median for index numbers?
Put them is ascending order. Count them = n. If n is odd, calculate (n+1)/2 the median is the value of the [(n+1)/2]th number in the ordered list. If n is even, the median is the average of the [n/2]th and [n/2 + 1]th numbers.
How can you find the total of the n numbers in a distribution if you know their mean?
Mean = Total of the numbers / n So total of the numbers = n*mean
How do you find the mean of first n natural numbers?
The sum of the first n natural numbers is n*(n+1)/2 There are n numbers so their mean = (n+1)/2
How do you find pairs of numbers which are equal?
Numbers. i^n = i^(n mod 4). With n = 27, 27 mod 4...
What five consecutive numbers make 115?
Let the consecutive numbers be n,n+1, n+2, n+3, & n+ 4. Add n + (n+1)+(n+2) + (n + 3) + ( n + 4) = 115 5n + 10 = 115 5n = 105 n = 21 N+1 = 22 n+2 = 23 n+3 = 24 n + 4 = 25 So the five consecutive numbers are 21,22,23,24 & 25.
Formula for finding the average?
To find the average of n numbers, take the sum of the numbers and divide by n.
