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The average of n numbers = (sum of n numbers) / (count of n numbers).
10m/n for any pair of counting numbers m and n such that m < n
Mean = (sum of the n numbers)/n
Mean = Total of the numbers / n So total of the numbers = n*mean
The sum of the first n natural numbers is n*(n+1)/2 There are n numbers so their mean = (n+1)/2