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Let the consecutive numbers be n,n+1, n+2, n+3, & n+ 4.

Add

n + (n+1)+(n+2) + (n + 3) + ( n + 4) = 115

5n + 10 = 115

5n = 105

n = 21

N+1 = 22

n+2 = 23

n+3 = 24

n + 4 = 25

So the five consecutive numbers are 21,22,23,24 & 25.

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lenpollock

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12y ago

You have five numbers that add up to 115. What is the average value of those five numbers? Now, how do you choose five consecutive numbers that have that average value?

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Q: What five consecutive numbers make 115?
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Related questions

What is the five consecutive numbers that add up to 115?

The numbers are 21, 22, 23, 24, and 25.


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115 + 116 = 131


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21,22,23,24,25---The Algebra Solution MethodFor any 5 consecutive numbers, starting with X, the four following are X+1, X+2, X+3, and X+4.The equation becomes X + (X+1) + (X+2) + (X+3) + (X+4) = 115So 5x + 10 = 115 and X =21---The Arithmetic Mean MethodAny five consecutive numbers will have an average or mean equal to the middle number. Knowing that 5 times that number is 115,5M = 115 and the central number M is 23.


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The numbers are 111, 113 and 115.


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How do you determine five numbers that have a mean of 23?

23*5 = 115 So pick any four numbers: integers, fractions, irrational numbers, whatever. Add them together to give a sum S. Let the 5th number be 115 - S Then: sum of all five numbers = (sum of the first four numbers) + (the fifth number) = S + (115 - S) = 115 And the count of numbers = 5 So mean = Sum/Count = 115/5 = 23


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Yes. Five is a factor of all cardinal (whole) numbers ending in five


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Chose any integer x. Three consecutive odd numbers: 2x+1 2x+3 2x+5 2x+5+2(2x+1)=115 2x+5+4x+2=115 6x+7=115 6x=108 x=18 The middle number is 2x+3=2*18+3 = 39


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57 and 58.