Q: What five consecutive numbers make 115?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

The numbers are 21, 22, 23, 24, and 25.

Let 'n' be the first odd number,. Then n+ 2 & n + 4 are the second and third odd number. Hence n + (n+2) + ( n + 4) = 339 Add 3n + 6 = 339 3n = 333 n = 111 n + 2 = 113 n + 4 = 115 Hence the three odd consecutive numbers are 111,113 & 115.

Since 115 ends in five, it will divide by '5'. Hence '5' is one of the factors. 5)115 = 23 Hence '23' is the other factor. Since '23' is a prime number, there are no other factors for 115 , but 5, and 23. except '1' & 115'.

gcf for these numbers 345 253 and 115 is 23.

23 x 5=115

Related questions

The numbers are 21, 22, 23, 24, and 25.

115 + 116 = 131

113, 114, 115

21,22,23,24,25---The Algebra Solution MethodFor any 5 consecutive numbers, starting with X, the four following are X+1, X+2, X+3, and X+4.The equation becomes X + (X+1) + (X+2) + (X+3) + (X+4) = 115So 5x + 10 = 115 and X =21---The Arithmetic Mean MethodAny five consecutive numbers will have an average or mean equal to the middle number. Knowing that 5 times that number is 115,5M = 115 and the central number M is 23.

The numbers are 111, 113 and 115.

114, 115 & 116

23*5 = 115 So pick any four numbers: integers, fractions, irrational numbers, whatever. Add them together to give a sum S. Let the 5th number be 115 - S Then: sum of all five numbers = (sum of the first four numbers) + (the fifth number) = S + (115 - S) = 115 And the count of numbers = 5 So mean = Sum/Count = 115/5 = 23

All numbers ending in five are odd.

Yes. Five is a factor of all cardinal (whole) numbers ending in five

The first ten consecutive composite positive integers are: 114 115 116 117 118 119 120 121 122 123

Chose any integer x. Three consecutive odd numbers: 2x+1 2x+3 2x+5 2x+5+2(2x+1)=115 2x+5+4x+2=115 6x+7=115 6x=108 x=18 The middle number is 2x+3=2*18+3 = 39

57 and 58.