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Let the consecutive numbers be n,n+1, n+2, n+3, & n+ 4.
Add
n + (n+1)+(n+2) + (n + 3) + ( n + 4) = 115
5n + 10 = 115
5n = 105
n = 21
N+1 = 22
n+2 = 23
n+3 = 24
n + 4 = 25
So the five consecutive numbers are 21,22,23,24 & 25.
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What is the five consecutive numbers that add up to 115?
The numbers are 21, 22, 23, 24, and 25.
What three consecutive odd numbers that have the sum of 339?
Let 'n' be the first odd number,. Then n+ 2 & n + 4 are the second and third odd number. Hence n + (n+2) + ( n + 4) = 339 Add 3n + 6 = 339 3n = 333 n = 111 n + 2 = 113 n + 4 = 115 Hence the three odd consecutive numbers are 111,113 & 115.
What numbers go into 115?
Since 115 ends in five, it will divide by '5'. Hence '5' is one of the factors. 5)115 = 23 Hence '23' is the other factor. Since '23' is a prime number, there are no other factors for 115 , but 5, and 23. except '1' & 115'.
What is the GCF of these numbers 345 253 and 115?
gcf for these numbers 345 253 and 115 is 23.
How do you write 115 in word?
115 is one hundred and fifteen.
