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Let the consecutive numbers be n,n+1, n+2, n+3, & n+ 4.
Add
n + (n+1)+(n+2) + (n + 3) + ( n + 4) = 115
5n + 10 = 115
5n = 105
n = 21
N+1 = 22
n+2 = 23
n+3 = 24
n + 4 = 25
So the five consecutive numbers are 21,22,23,24 & 25.
What else can I help you with?
What is the five consecutive numbers that add up to 115?
The numbers are 21, 22, 23, 24, and 25.
What three consecutive odd numbers that have the sum of 339?
Let 'n' be the first odd number,. Then n+ 2 & n + 4 are the second and third odd number. Hence n + (n+2) + ( n + 4) = 339 Add 3n + 6 = 339 3n = 333 n = 111 n + 2 = 113 n + 4 = 115 Hence the three odd consecutive numbers are 111,113 & 115.
What numbers go into 115?
Since 115 ends in five, it will divide by '5'. Hence '5' is one of the factors. 5)115 = 23 Hence '23' is the other factor. Since '23' is a prime number, there are no other factors for 115 , but 5, and 23. except '1' & 115'.
What is the GCF of these numbers 345 253 and 115?
gcf for these numbers 345 253 and 115 is 23.
How do you write 115 in word?
115 is one hundred and fifteen.
What is the five consecutive numbers that add up to 115?
The numbers are 21, 22, 23, 24, and 25.
What are the two consecutive numbers that equal 131?
115 + 116 = 131
What 3 consecutive numbers add up to 342?
113, 114, 115
What five consecutive numbers added together have a sum of 115?
21,22,23,24,25---The Algebra Solution MethodFor any 5 consecutive numbers, starting with X, the four following are X+1, X+2, X+3, and X+4.The equation becomes X + (X+1) + (X+2) + (X+3) + (X+4) = 115So 5x + 10 = 115 and X =21---The Arithmetic Mean MethodAny five consecutive numbers will have an average or mean equal to the middle number. Knowing that 5 times that number is 115,5M = 115 and the central number M is 23.
What 3 consecutive numbers equal 345 when added up?
114, 115 & 116
What are three odd consecutive integers that equal 339?
The numbers are 111, 113 and 115.
Is 115 a even number?
All numbers ending in five are odd.
How do you determine five numbers that have a mean of 23?
23*5 = 115 So pick any four numbers: integers, fractions, irrational numbers, whatever. Add them together to give a sum S. Let the 5th number be 115 - S Then: sum of all five numbers = (sum of the first four numbers) + (the fifth number) = S + (115 - S) = 115 And the count of numbers = 5 So mean = Sum/Count = 115/5 = 23
Is 5 a factor of 115?
Yes. Five is a factor of all cardinal (whole) numbers ending in five
What are the first ten consecutive composite numbers?
The first ten consecutive composite positive integers are: 114 115 116 117 118 119 120 121 122 123
Three consecutive odd counting numbers have the property that the sum of the largest and twice the smallest is 115 what is the middle number?
Chose any integer x. Three consecutive odd numbers: 2x+1 2x+3 2x+5 2x+5+2(2x+1)=115 2x+5+4x+2=115 6x+7=115 6x=108 x=18 The middle number is 2x+3=2*18+3 = 39
What are two consecutive integers to 115?
57 and 58.
