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What is the sum of one third of a number and 27?
n/3 + 27
What 2 equal numbers have the sum 54?
The two equal numbers that have the sum of 54 are 27 and 27.
The sum of a number and 2?
let the number be n, then the sum of the number and 2 is n+2
The sum of a number and 8?
This is simple algebra. Let the unknown number be n. Then the sum of this number and 8 = n + 8.
The sum of two numbers is 27 One number is 2 times as large as the other What are the numbers?
Let the number be 'n' & '2n' , Since '2n' is twice as large as 'n'. Hence 2n + n = 27 3n = 28 Divide both sides by '3' n = 9 Hence 2n - 18 Verification 9 + 18 =27
The sum of 27 and a number n?
27+n=n+27
What is the sum of one third of a number and 27?
n/3 + 27
The sum of three consecutive numbers is 27 what is the least number?
n + (n + 1) + (n + 2) = 27 3n + 3 = 27 n = 8 Thus, the numbers are 8, 9, and 10, and the least of these is 8.
What is the product of 9 and the sum of a number and -3?
12
What 2 equal numbers have the sum 54?
The two equal numbers that have the sum of 54 are 27 and 27.
The sum of a number and 2?
let the number be n, then the sum of the number and 2 is n+2
A sum of a number and twice its number?
If the number is n, then twice the number is 2n and the sum of the two is n + 2n = 3n.
What is the sum of the interior angles of a regular polygon with 27 sides?
The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees. Here, n = 27, so the sum of the interior angles is (27-2)*180 = 25*180 = 4500 degrees.
The sum of a number and 6?
n = number n + 6 ======
The sum of a number and 8?
This is simple algebra. Let the unknown number be n. Then the sum of this number and 8 = n + 8.
C program to find sum of 'n' number using function?
void main () { int no1, sum, n; clrscr() sum = 0; n = 1; printf("\n enter the number to which sum is to be generated"); scanf("%d",&no1); while(n<=no1) { sum=sum+n; n=n+1 } printf("\n the sum of %d = %d, no1, sum"); getch (); }
Write a java program to find out the sum of a number of n digits?
class Sum_Of_Digits { public static void printSumandnoofdigits(int n) { int temp = n; int count = 0; int sum = 0; while ( n > 0 ) { sum = sum + n % 10; n = n / 10; count ++; } System.out.println("The number is..." + temp ); System.out.println("The sum of digits is..." + sum); System.out.println("The number of digits is..." + count); } }
