The sum of the first 50 even numbers is 2,550.
The sum of the first 10,000 even numbers is 100,010,000.
The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.
You do not need a conjecture; you can calculate the answer. The answer is 10,100
There are no two consecutive even numbers whose sum is 100. It is easily proved.
The sum of the first 100 positive even numbers is 10,100.
The sum of the first 100 even numbers is 10,100
The sum of all the first 100 even numbers is 10,100.
The sum of the first 100 positive even numbers can be calculated using the formula for the sum of an arithmetic series: n*(first term + last term)/2. In this case, the first term is 2, the last term is 200, and n is 100. Therefore, the sum is 10,100.
n*(n+1)=sum 100*(100+1)=10100
The sum of the first 100 numbers, excluding zero, is 5,001.
The sum of the first 100 odd numbers is 10,000.
The sum of the 25 primes less than 100 is even (it is 1060).The first prime number is 2. Every other prime number is odd.So, of the 25 primes less than 100, one is even and 24 are odd.Any two odd numbers sum to an even number. Therefore, an even number of odd numbers has an even sum. So the sum of 24 odd numbers is even.Therefore, the sum of the 25 primes less than 100 is even.
The sum of the first 50 even numbers is 2,550.
The sum of the first 10,000 even numbers is 100,010,000.
The sum of the cubes of the first 100 whole numbers is 25,502,500.
The sum of the first 10 even numbers is 110.