1/1 + 1/1 + 1/1
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(1+1+1)! = 3! = 3x2x1 = 6... :)
15 638 can be made with 1 ten, 5 ones, 6 hundreds, 3 tens, and 8 ones; 1 ten, 8 ones, 6 hundreds, 3 tens, and 5 ones; or 6 ones, 5 hundreds, 3 tens, 8 ones, and 1 ten.
Four ones make 4 and three ones make 3... and forty-three ones make 43.
No, a multiple of 6 cannot have a ones digit equal to 3. The ones digit of a multiple of 6 will always be even, either 0, 2, 4, 6, or 8, because 6 is divisible by 2.
6 + 7 = 13 13 can't fit into the ones place. Regroup 13 ones into one ten and three ones. Leave the three ones in the ones place and carry the one ten over to the tens place.