The equation you've provided seems to contain a typographical error, as it combines two elements improperly. If you meant to write the equation (y = -2x - 1), you could graph it by plotting the y-intercept at (0, -1) and using the slope of -2 to find another point, such as (1, -3). Draw a straight line through these points to represent the equation. If this isn't what you meant, please clarify the equation for further assistance.
3
Yes, that is a shifted tanX graph, just as you would shift any graft.
Well I cant graph it for you but its a linear line some points would be (0,-1) (1,-2) (2,-3)(3,-4) (-1,0) (-2,1) (-3,2) and so on
y 2 1 x 0 1 2
The lines are parallel.
Any graph with the slope of -1/2
y=x+1 there for answer is 2
3
Yes, that is a shifted tanX graph, just as you would shift any graft.
1
Well I cant graph it for you but its a linear line some points would be (0,-1) (1,-2) (2,-3)(3,-4) (-1,0) (-2,1) (-3,2) and so on
y 2 1 x 0 1 2
It would be a circle, centered at the origin, with a radius of 2.
It would be less steep
5
the graph is 2 straight lines from the origin in quadrants 1 and 2 at angle of 45 and 135 degrees from 0
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.