3
Yes, that is a shifted tanX graph, just as you would shift any graft.
Well I cant graph it for you but its a linear line some points would be (0,-1) (1,-2) (2,-3)(3,-4) (-1,0) (-2,1) (-3,2) and so on
y 2 1 x 0 1 2
The lines are parallel.
Any graph with the slope of -1/2
y=x+1 there for answer is 2
3
Yes, that is a shifted tanX graph, just as you would shift any graft.
1
Well I cant graph it for you but its a linear line some points would be (0,-1) (1,-2) (2,-3)(3,-4) (-1,0) (-2,1) (-3,2) and so on
y 2 1 x 0 1 2
It would be a circle, centered at the origin, with a radius of 2.
It would be less steep
the graph is 2 straight lines from the origin in quadrants 1 and 2 at angle of 45 and 135 degrees from 0
5
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.