Yes.
You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
what is the anwer for x=3 and x=2
The graph of [ y = -3x ] is a straight line, through the origin, with slope of -3 .
The vertex of the graph Y 3 X-12 plus 2 would be -1/3 and -4/3. This is taught in math.
Becuase 7 divided by 2 is 3.5, you would put it on the graph imbetween 3 and 4!(:
Yes.
The points on the graph would be as follows(-2,-9) (-1,-6) (0,-3) (1,0) (2,3) (3,6)This will give you the position of the line if you need more points just extend the line of your graph.
The term "cyclic graph" is not well-defined. If you mean a graph that is not acyclic, then the answer is 3. That would be the union of a complete graph on 3 vertices and any number of isolated vertices. If you mean a graph that is (isomorphic to) a cycle, then the answer is n. If you are really asking the maximum number of edges, then that would be the triangle numbers such as n (n-1) /2.
To graph a negitive . You would go three spaces back from zero.
Graph the following Inequalities: x > 3
y=2/3-(-2) ? The "-(-2)" would become a positive 2, so the y-intercept would be 2. Then, from there, you move up 2 spaces on the graph and over to the right 3 spaces, and place a point. Then, do the same thing repeatedly from that point - up 2 and to the right 3 - and keep placing another point until you don't have any more graphing space.
Move 3 over the right side of the equation so the equation would be x = -3. The graph of this would be a verticle line at x= -3
You may mean, what is the graph of the function y = x^2 + 3. This graph shows a upward parabola with a y-intercept of 3 and a minimum at x=0.
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
what is the anwer for x=3 and x=2