This is one way to do it
1) Find the x and y -intercepts
y = -3x + 6
Plug in 0 for "x" and solve for "y"
y = -3(0) + 6
y = 6
That means that when x = 0, y = 6
So plot the first point (0, 6) onto the graph <-- this is your x-intercept by the way
Next do the opposite by plugging in 0 for "y" and solve for "x"
y = -3x + 6
0 = -3x + 6
3x = 6
x = 2
That means that when y = 0, x = 2
Plot the point (0,2) on the graph. This is your y-intercept.
Now, you can just connect the two points and you will get your line.
The lines are parallel.
They are the same equation just written differently so they are both easy to graph.
The starting point on the y-axis changes from -2 to 6.
3x + y = -1 y = -3x - 1 The graph is a straight line, with a slope of -3, passing through the point Y = -1 on the y-axis.
3x + 2 = 3x + 6 This is not possible.
The lines are parallel.
The graph of [ y = -3x ] is a straight line, through the origin, with slope of -3 .
First of all, if 'x' is 3, then 'x' doesn't equal -3x+3 . You must mean y = -3x + 3.If x=3, then (-3x + 3) = -6 .The graph is the point (3, -6) .
They are the same equation just written differently so they are both easy to graph.
The starting point on the y-axis changes from -2 to 6.
3x + y = c where c is any constant number of your choice.
(a) y = -3x + 1
3x + y = -1 y = -3x - 1 The graph is a straight line, with a slope of -3, passing through the point Y = -1 on the y-axis.
3x + 2 = Y
no
3x + 2 = 3x + 6 This is not possible.
A straight line, passing through the point (0,5) with a gradient of -3.