-3
solve the x and you find the y
-10
The x intercept would be 14 and the y intercept would be 6.
To find the y intercept put zero in for x and solve. To find the x intercept put zero in for y and solve. (0,8) and (-8,0)
To find the y-intercept you substitute in 0 for x and solve. To find the x- intercept you substitute in 0 for y and solve. If you do it correctly you should find the x-intercept to be -3 and the y-intercept to be 3.
-3
Your equation does not have an x variable. So as-is would be a horizontal line (no x-intercept). If this was a typo and you meant to have x in one of the terms then it would have an x and y intercept. The y intercept is where it intersects the y-axis. The x coordinate of the y-axis is x=0, so substitute x=0 into the equation, and solve for y. To find the x-intercept, substitute y=0, and solve for x.
solve the x and you find the y
-10
The x intercept would be 14 and the y intercept would be 6.
To find the y intercept put zero in for x and solve. To find the x intercept put zero in for y and solve. (0,8) and (-8,0)
Normally, the y-intercept would be after the x term, but because there is no x term the y-intercept is 0.
Put 0 in for x and solve for y to find the y intercept. Put 0 in for y and solve for x to find the x intercept. -4(0)+3y=10 y=10/3 y intercept is (0,10/3) -4x+3(0)=10 x=-10/4 x intercept is (-10/4,0)
10
-6
No. If you let 'x' =0 then 'x' is zero and there's no reason to solve for it.At the x-intercept ... just like at any point on the x-axis ... 'y' is zero.Let 'y' equal zero, then solve for 'x'.