It would be: 2x+4 = 19 and the value of x works out as 7.5
It would be: 2x+4 = 19
"the sum of 2" and "twice" "a number" "is" "36"2+2x=36 â–
Twice a number would be written as 2x.
2 + 2x = 36
13 < 2n - 5 < 21
It would be: 2x+4 = 19
3a-6x2
"the sum of 2" and "twice" "a number" "is" "36"2+2x=36 â–
Twice a number would be written as 2x.
2 + 2x = 36
the quotient of twice a number and six is.... 2x/6 four less than three times the same number is .... 3x-4 So the equation would be 2x/6=3x-4
13 < 2n - 5 < 21
It is: 2x+11 = -1 and the vaue of x works out as -6
43
2t/12
2n - 4
To write out the given statement algebraically, you would start by defining the variable for the number, let's say it is represented by 'x'. The equation would be: 6x - 5 < 2x + 10. This equation represents the statement "Six times a number minus five is less than twice the number plus ten" in algebraic form. To solve this inequality, you would isolate the variable 'x' by performing operations to simplify and find the range of values that satisfy the inequality.