I'm assuming you're talking about the equation for a graph here.
If you think about the axes on the graph, the y-axis occurs at x = 0, and the x-axis at y = 0. So, to find out where the line crosses the y-axis (or y-intercept), simply set x = 0 in the equation. Example:
y = 3x+7
when x = 0, y = 3 x 0 + 7, so y = 7
therefore the y-intercept is 7
To find the x-intercept, simply set y = 0 in the equation. This can be more difficult, especially if it has more than x cubed in it (there are formulae that can be used to solve polynomials, but they can get complicated). Examples:
y = 3x+7
when y = 0, 0 = 3x+7, so 3x = -7, and thus x = -7/3
therefore the x-intercept is -7/3
y = x^2+6x+8
when y = 0, x^2+6x+8 = 0, therefore x = -2 or -4
therefore the x-intercepts are -2 and -4
y = x^3+9x^2+30x+24
when y = 0, x^3+9x^2+30x+24 = 0, therefore x = -2, -3 or -4
therefore the x-intercepts are -2, -3 and -4
It depends on the vertex of what!
If the discriminant is negative, there are 0 interceptsIf the discriminant is zero, there is 1 interceptIf the discriminant is positive, there are 2 intercepts
Your x and y intercepts give you two points on the line of the graph. Use these two points in the slope equation m = (y2-y1)/(x2-x1), and that gives you the slope.
Find values of the variable for which the value of the polynomial is zero.
Slope: -1 intercepts: (0,1000),(1000,0)
no...
Yes, the places where the graph of a polynomial intercepts the x-axis are zeros. The value of y at those places must be 0 for the polynomial to intersect the x axis.
1
set the values of the y equal to zero
It depends on the vertex of what!
The graph of a polynomial in X crosses the X-axis at x-intercepts known as the roots of the polynomial, the values of x that solve the equation.(polynomial in X) = 0 or otherwise y=0
If the discriminant is negative, there are 0 interceptsIf the discriminant is zero, there is 1 interceptIf the discriminant is positive, there are 2 intercepts
Evaluating a Polynomial expression using a singly linked list visit : http://myfundatimemachine.blogspot.in/2012/06/polynomial-evaluation-in-c.html
The vertex must be half way between the two x intercepts
Your x and y intercepts give you two points on the line of the graph. Use these two points in the slope equation m = (y2-y1)/(x2-x1), and that gives you the slope.
y = -xBoth intercepts are at the origin. From there, the line slopes up to the leftand down to the right.
Each distinct real root is an x-intercept. So the answer is 4.