It depends on the vertex of what!
The x-intercept of an equation is any location where on the equation where x=0. In the case of a parabolic function, the easiest way to obtain the x intercept is to change the equation into binomial form (x+a)(x-b) form. Then by setting each of those binomials equal to zero, you can determine the x-intercepts.
To determine the intercepts of a line, you need to find where the line crosses the x-axis and y-axis. The x-intercept occurs when y = 0, and the y-intercept occurs when x = 0. If you have the equation of the line, you can substitute these values to find the respective intercepts. Please provide the equation of the line for specific intercept values.
To find the intercepts of the equation (6x + 8y = 24), we can set (y = 0) to find the x-intercept: [ 6x = 24 \implies x = 4 ] Thus, the x-intercept is ((4, 0)). Setting (x = 0) to find the y-intercept gives: [ 8y = 24 \implies y = 3 ] So, the y-intercept is ((0, 3)). Therefore, the intercepts are ((4, 0)) and ((0, 3)).
X intercept = -4 Y intercept = 2
The x intercept would be 14 and the y intercept would be 6.
The vertex must be half way between the two x intercepts
find the x-intercepts of the parabola with vertex (7,-12) and y-intercept (0,135). write your answer in this form:(x1,y1),(x2,y2). if necessary, round to the nearest hundredth.
The x-intercept of an equation is any location where on the equation where x=0. In the case of a parabolic function, the easiest way to obtain the x intercept is to change the equation into binomial form (x+a)(x-b) form. Then by setting each of those binomials equal to zero, you can determine the x-intercepts.
To determine the intercepts of a line, you need to find where the line crosses the x-axis and y-axis. The x-intercept occurs when y = 0, and the y-intercept occurs when x = 0. If you have the equation of the line, you can substitute these values to find the respective intercepts. Please provide the equation of the line for specific intercept values.
To find the intercepts of the equation (6x + 8y = 24), we can set (y = 0) to find the x-intercept: [ 6x = 24 \implies x = 4 ] Thus, the x-intercept is ((4, 0)). Setting (x = 0) to find the y-intercept gives: [ 8y = 24 \implies y = 3 ] So, the y-intercept is ((0, 3)). Therefore, the intercepts are ((4, 0)) and ((0, 3)).
24
X intercept = -4 Y intercept = 2
To find the y-intercept you substitute in 0 for x and solve. To find the x- intercept you substitute in 0 for y and solve. If you do it correctly you should find the x-intercept to be -3 and the y-intercept to be 3.
The x intercept would be 14 and the y intercept would be 6.
Then there is no x-intercept. No big deal. Lots of functions do not have x- intercepts. For example, y = x2 + 1 or y = 2x
To find the x and y intercepts of an equation, set y to 0 to find the x-intercept (solve for x), and set x to 0 to find the y-intercept (solve for y). For example, in the equation (y = 2x + 4), the x-intercept is found by setting (y = 0), giving (x = -2), and the y-intercept is found by setting (x = 0), yielding (y = 4). If you provide specific equations, I can calculate their intercepts for you.
The y-intercept is c in the standard form. The x-intercept is -c/m.