999 + 999/999 = 1000
If you allow non integers, then your smallest four-digit number would be .0001. If you only allow integers, then your smallest four-digit number would be 1000. Your largest four-digit number would be 9999.
222335
There is no number. 100 is the only one that has a hundreds digit. It's impossible.
There might be more than one answer but I came up with this; 8x8x8= 512 8x8x8= 512 8+8+8=24 So if you add the first two numbers (512 twice) that makes 1024. Then you simply minus the last number which is 24 and it equals 1000. The total number of 8's also equal 9. Enjoy :] ----------------------------------------------------------------------------------------------- Unfortunately the first answer I gave used 9 8's whilst you were only allowed 8 of the chosen digit. Here's my second attempt; If you add two 5's together it equals 10 Do this two more times. So you have three 10's. Now simply times these together. So that's: (5+5)(5+5)(5+5)= 1000 There you go finally and I only used the digits 6 times! ;D ============================== Hi, And the correct answer is (8*8+8*8)*8-(8+8+8) Here one digit is used exactly eight times
1 mm = 1000 micrometre is written as a decimal. To write a number as a decimal only requires that the place value of each digit is ten times the place value of the digit to its right. The number may or may not have a decimal point, it may or may not have a fractional part.
1008
Assuming you mean in the numbers 1, 2, 3, ..., 998, 999, 1000 then the digit 0. (The digit 1 appears 301 times, the digits 2-9 all appear 300 times each, but the digit 0 only appears 192 times.)
Given: Total sum = 1000 To find: Terms (using 8) that adds up to 1000 =? Solution: The given question has the following conditions: Using number 8 only 8 times Addition of terms only Step 1: Write number 8 for 8 times which is equal to 100 => 8 8 8 8 8 8 8 8 = 1000 Step 2: Consider the 3 digit number made of 8 => 3 digit number = 888 => 8 used 3 times Step 3: Consider the 2 digit number made of 8 => 2 digit number = 88 => 8 used 2 times Step 4: Consider 1 digit number made of 8 => 1 digit number= 8 + 8 + 8 => 8 used 3 times To sum up: => 888 + 88 + 8 + 8 + 8 = 1000 Hence by adding up all terms using 8 we get 1000.
-9999. Or, if only positive numbers are being considered, then, 1000.
Yes, 888+88+8+8+8=1000
If you allow non integers, then your smallest four-digit number would be .0001. If you only allow integers, then your smallest four-digit number would be 1000. Your largest four-digit number would be 9999.
222335
The smallest six-digit even number is 100,000
There is no number. 100 is the only one that has a hundreds digit. It's impossible.
It depends. If you can only use each number once, there are 720 combinations. If you can use numbers multiple times, then there are 1000 combinations, by using all numbers from 000 to 999.
There might be more than one answer but I came up with this; 8x8x8= 512 8x8x8= 512 8+8+8=24 So if you add the first two numbers (512 twice) that makes 1024. Then you simply minus the last number which is 24 and it equals 1000. The total number of 8's also equal 9. Enjoy :] ----------------------------------------------------------------------------------------------- Unfortunately the first answer I gave used 9 8's whilst you were only allowed 8 of the chosen digit. Here's my second attempt; If you add two 5's together it equals 10 Do this two more times. So you have three 10's. Now simply times these together. So that's: (5+5)(5+5)(5+5)= 1000 There you go finally and I only used the digits 6 times! ;D ============================== Hi, And the correct answer is (8*8+8*8)*8-(8+8+8) Here one digit is used exactly eight times
-996