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Make numbers that add to 1000 using only one digit you choose 1-9 you can only use your digit 8 times?
There might be more than one answer but I came up with this;
8x8x8= 512
8x8x8= 512
8+8+8=24
So if you add the first two numbers (512 twice) that makes 1024.
Then you simply minus the last number which is 24 and it equals 1000.
The total number of 8's also equal 9.
Enjoy :]
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Unfortunately the first answer I gave used 9 8's whilst you were only allowed 8 of the chosen digit.
Here's my second attempt;
If you add two 5's together it equals 10
Do this two more times.
So you have three 10's.
Now simply times these together.
So that's: (5+5)(5+5)(5+5)= 1000
There you go finally and I only used the digits 6 times! ;D
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Hi,
And the correct answer is
(8*8+8*8)*8-(8+8+8)
Here one digit is used exactly eight times
What else can I help you with?
What are the the 3 digit numbers using 1345678?
Using the digits of 1345678, there are 210 three digit numbers in which no digit is repeated.
How many digit numbers can be formed from the digit 2 3 5 7 8?
To determine how many digit numbers can be formed using the digits 2, 3, 5, 7, and 8, we need to consider the number of digits in the numbers we are forming. For a 1-digit number, we can use any of the 5 digits. For a 2-digit number, we can choose 2 out of the 5 digits and arrange them, giving us (5 \times 4) combinations. We can continue this for 3-digit, 4-digit, and 5-digit numbers, which will yield (5), (20), (60), and (120) respectively. Therefore, the total number of digit numbers is (5 + 20 + 60 + 120 = 205).
How many four digits can be formed in 1 2 3 4 5 and 6 without repeating the numbers?
To form a four-digit number using the digits 1, 2, 3, 4, 5, and 6 without repeating any digits, you can choose the first digit in 6 ways, the second digit in 5 ways, the third digit in 4 ways, and the fourth digit in 3 ways. Therefore, the total number of four-digit combinations is calculated as (6 \times 5 \times 4 \times 3 = 360). Thus, 360 different four-digit numbers can be formed.
How many 2 digit odd numbers can be formed using the digits 123456789 without repitition?
To form a two-digit odd number using the digits 123456789 without repetition, the unit's digit must be an odd number. The available odd digits are 1, 3, 5, 7, and 9, giving us 5 options for the unit's place. For the ten's place, we can choose any of the remaining 8 digits. Therefore, the total number of two-digit odd numbers is (5 \times 8 = 40).
How many four digit numbers can be made using the digits 0123567?
To form a four-digit number using the digits 0, 1, 2, 3, 5, 6, and 7, we must ensure that the first digit is not 0 (to avoid creating a three-digit number). This leaves us with 6 options for the first digit (1, 2, 3, 5, 6, 7). For the remaining three digits, we can use any of the 7 digits (including 0) and can repeat digits. Thus, the total number of four-digit numbers is calculated as follows: (6 \times 7 \times 7 \times 7 = 6 \times 343 = 2058). Therefore, there are 2058 possible four-digit numbers.
What are the the 3 digit numbers using 1345678?
Using the digits of 1345678, there are 210 three digit numbers in which no digit is repeated.
How many two digit numbers can you form using the digits 1235679 with repetition allowed?
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
How many 3 digit numbers can you make using only 1 and 2 using it as many times as you want?
8 of them.
How many digit numbers can be formed from the digit 2 3 5 7 8?
To determine how many digit numbers can be formed using the digits 2, 3, 5, 7, and 8, we need to consider the number of digits in the numbers we are forming. For a 1-digit number, we can use any of the 5 digits. For a 2-digit number, we can choose 2 out of the 5 digits and arrange them, giving us (5 \times 4) combinations. We can continue this for 3-digit, 4-digit, and 5-digit numbers, which will yield (5), (20), (60), and (120) respectively. Therefore, the total number of digit numbers is (5 + 20 + 60 + 120 = 205).
Using the digit 8 8 times and no other digit add numbers together to reach a sum of 1000?
888, 88, 8, 8, 8.
How many four digits can be formed in 1 2 3 4 5 and 6 without repeating the numbers?
To form a four-digit number using the digits 1, 2, 3, 4, 5, and 6 without repeating any digits, you can choose the first digit in 6 ways, the second digit in 5 ways, the third digit in 4 ways, and the fourth digit in 3 ways. Therefore, the total number of four-digit combinations is calculated as (6 \times 5 \times 4 \times 3 = 360). Thus, 360 different four-digit numbers can be formed.
What are the 3 digit numbers using any digit repeated in 357?
There are 27 of them.
If using 7 single digit numbers how many different combinations can you get?
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
How many 2 digit odd numbers can be formed using the digits 123456789 without repitition?
To form a two-digit odd number using the digits 123456789 without repetition, the unit's digit must be an odd number. The available odd digits are 1, 3, 5, 7, and 9, giving us 5 options for the unit's place. For the ten's place, we can choose any of the remaining 8 digits. Therefore, the total number of two-digit odd numbers is (5 \times 8 = 40).
How many four digit numbers can be made using the digits 0123567?
To form a four-digit number using the digits 0, 1, 2, 3, 5, 6, and 7, we must ensure that the first digit is not 0 (to avoid creating a three-digit number). This leaves us with 6 options for the first digit (1, 2, 3, 5, 6, 7). For the remaining three digits, we can use any of the 7 digits (including 0) and can repeat digits. Thus, the total number of four-digit numbers is calculated as follows: (6 \times 7 \times 7 \times 7 = 6 \times 343 = 2058). Therefore, there are 2058 possible four-digit numbers.
How many different three digit numbers can be written using the digits 1 through 9?
You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.
How many ways can you choose a 3 digit password using 0-9 without repeating the numbers?
10 x 9 x 8 = 720.
