x = 1
Add all the numbers and divide that by the number of numbers.
You divide the head with the tail and do some dancing
The sequence given is an arithmetic sequence where the first term is -29 and the common difference is 8 (calculated as -21 - (-29)). To find the 7th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ). Substituting ( a_1 = -29 ), ( d = 8 ), and ( n = 7 ), we get ( a_7 = -29 + (7-1) \cdot 8 = -29 + 48 = 19 ). Thus, the 7th term is 19.
You need to find the perimeter at the first few iterations and find out what the sequence is. It could be an arithmetic sequence or a polynomial of a higher degree: you need to find out the generating polynomial. Then substitute the iteration number in place of the variable in this polynomial.
You need an equation for the nth term of the sequence, or some other means of identifying the sequence. In general, they will be a+n, a+2n, a+3n and a+4n although some go for a, a+n, a+2n and a+3n.
The 90th term of the arithmetic sequence is 461
The difference between successive terms in an arithmetic sequence is a constant. Denote this by r. Suppose the first term is a. Then the nth term, of the sequence is given by t(n) = (a-r) + n*r or a + (n-1)*r
i dont get it
An arithmetic sequence.
27,33,39
It is a sequence of numbers which is called an arithmetic, or linear, sequence.
The following formula generalizes this pattern and can be used to find ANY term in an arithmetic sequence. a'n = a'1+ (n-1)d.
Add all the numbers and divide that by the number of numbers.
You divide the head with the tail and do some dancing
A single number, such as 13579, does not define a sequence.
From any term after the first, subtract the preceding term.
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