The difference between successive terms in an arithmetic sequence is a constant. Denote this by r.
Suppose the first term is a. Then the nth term, of the sequence is given by
t(n) = (a-r) + n*r or a + (n-1)*r
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It appears that a number of -79 is missing in the sequence and so if you meant -58 -65 -72 -79 -86 then the nth term is -7n-51 which makes 6th term in the sequence -93
The nth term is referring to any term in the arithmetic sequence. You would figure out the formula an = a1+(n-1)d-10where an is your y-value, a1 is your first term in a number sequence (your x-value), n is the term you're trying to find, and d is the amount you're increasing by.
Well, honey, looks like we've got ourselves an arithmetic sequence here with a common difference of 7. So, to find the nth term, we use the formula a_n = a_1 + (n-1)d. Plug in the values a_1 = 12, d = 7, and n to get the nth term. Math doesn't have to be a drag, darling!
It is a + 8d where a is the first term and d is the common difference.
tn = a + (n - 1)d where a is the first term and d is the difference between each term.