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X equals 1 and y equals 6 what is the point of intersection?
1,6
What are the points of intersection of the line x -y equals 2 with x squared -4y squared equals 5?
The points of intersection are: (7/3, 1/3) and (3, 1)
What are the points of intersection of 3x -2y -1 equals 0 with 3x squared -2y squared equals -5 on the Cartesian plane?
Points of intersection work out as: (3, 4) and (-1, -2)
What is the point of intersection for y equals 2x -1?
3
What is the point of intersection if y equals x plus 1 and x equals -x plus 1x?
2
X equals 1 and y equals 6 what is the point of intersection?
1,6
What are the points of intersection of the line x -y equals 2 with x squared -4y squared equals 5?
The points of intersection are: (7/3, 1/3) and (3, 1)
What are the points of intersection of 3x -2y -1 equals 0 with 3x squared -2y squared equals -5 on the Cartesian plane?
Points of intersection work out as: (3, 4) and (-1, -2)
Where are the points of intersection of the equations 4y squared -3x squared equals 1 and x -2y equals 1?
The points of intersection of the equations 4y^2 -3x^2 = 1 and x -2 = 1 are at (0, -1/2) and (-1, -1)
What is the point of intersection for y equals 2x -1?
3
What is the point of intersection if y equals x plus 1 and x equals -x plus 1x?
2
What are the order pairs for x plus 7y equals 12 and 3x - 5y equals 10?
x = 5 and y =1 Intersection at (5, 1)
What is Intersection of Sets?
You need two sets to have an intersection. If you have two sets, call them R and S, then their intersection is the set T that contains all elements of R that also belong to S OR all elements of S and also belong to R...it's the same thing.
What is the point of intersection between the lines y equals 4x -1 and 3y -8x plus 2 equals 0?
The point of intersection of the given simultaneous equations of y = 4x-1 and 3y-8x+2 = 0 is at (0.25, 0) solved by means of elimination and substitution.
Where is the point of intersection of the lines y equals 4x-1 and 3y-8x plus 2 equals 0?
By a process of elimination and substitution the lines intersect at: (1/4, 0)
How do you find the point of intersection between x2 plus y2 equals 5 and x-y equals 1?
x-y = 1 => x = y+1 x2+y2 = 5 => (y+1)(x+1)+y2 = 5 2y2+2y-4 = 0 y = -2 or y = 1 So the points of intersection are: (-1, -2) and (2, 1)
How many solutions to y equals x-1 and y equals -x plus 1?
y = x - 1 y = -x + 1 (add both the equations) 2y = 0 y = 0 when y = 0, x = 1 So that the only solution is the intersection point of the lines, (1, 0).
