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The diagonals arenotthe sides. They're lines you draw from one angle of the parallelogram to the angle opposite it. So if you have parallelogram ABCD, your diagonals are AC and BD, because AB, BC, CD, and DA are all sides.
A Rectangle is a quadrilateral (four sided polygon) with two pairs of equal and parallel sides (opposite sides are parallel and equal, one pair is usually a different length from the other pair but if they are equal it is called a square), and all angles are right angles (90°). It has two diagonals which have the properties:The diagonals are always congruent (of equal length);The diagonals bisect each other (cut each other into two equal parts);The diagonals do not bisect the angles (unless the rectangle is a square when they do);The diagonals are not perpendicular (unless the rectangle is a square when they do).PROOF of the diagonals congruent:Take a rectangle ABCD with diagonals AC and BD.Using Pythagoras on the triangles ACD and BCD:AC² = AD² + CD²BD² = BC² + CD²But as ABCD is a rectangle AD = BC since they are opposite and parallel; thus:AC² = AD² + CD² = BC² + CD² = BD²Thus, as AC and BD are the diagonals, they are equal.Therefore the diagonals of a rectangle are congruent.
No. If two lines intersect they cross each other. To bisect each other, means that the lines not only intersect but that also that the point where the two line[ segment]s cross is the mid point of both of the line[ segment]s. Examples, consider: The diagonals of a kite ABCD with sides AB & AD equal (2 cm each), and BC & DC equal and twice the length of the other two sides (4 cm each). The diagonals AC and BD intersect each other; BD is bisected by AC but AC is NOT bisected by BD. The diagonals of a right angle trapezium ABCD with ∠DAB and ∠ADC right angles (so sides AB and DC are parallel) and with sides AB = 2 cm, CD = 14 cm and AD = 5 cm (side BC = 13 cm). The diagonals AC and BD intersect, but NEITHER bisects the other. The diagonals AC and BD of a square ABCD not only intersect each other, but they also do, in this case, bisect each other.
Let ABCD be a rectangleAB = CD = 9 ftBC = DA(AB)x(BC) = 54 ftBC = 54/(AB) = 54/9 = 6 ftperimeter = (AB)+(BC)+(CD)+(DA) = 2(AB)+2(BC) = 2x9+2x6 = 30 ft
No, four lines can can have 6 total intersections. They would be Ab, Ac, Ad, Bc, Bd, and Cd
Yes. Since they are rational numbers, let's call the first one a/b and the second one c/d where a,b,c, and d are integers. Now we can subtract by finding a common denominator. Let's use bd. So we have ad/bd-cb/bc= (ad-bc)/CD which is rational since we know ad and bc are integers being the product of integers and CD is also an integers. Call ad-bd=P and call CD=Q where P and Q are integers. We now see the difference is of two rationals is rational.
Six. If the sides are labelled a, b, c and d then the congruent pairs are: ab, ac, ad, bc, bd and cd
You cannot prove it since it is not true for a general quadrilateral.
segments AB, CD, BD.
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shift
The diagonals arenotthe sides. They're lines you draw from one angle of the parallelogram to the angle opposite it. So if you have parallelogram ABCD, your diagonals are AC and BD, because AB, BC, CD, and DA are all sides.
A Rectangle is a quadrilateral (four sided polygon) with two pairs of equal and parallel sides (opposite sides are parallel and equal, one pair is usually a different length from the other pair but if they are equal it is called a square), and all angles are right angles (90°). It has two diagonals which have the properties:The diagonals are always congruent (of equal length);The diagonals bisect each other (cut each other into two equal parts);The diagonals do not bisect the angles (unless the rectangle is a square when they do);The diagonals are not perpendicular (unless the rectangle is a square when they do).PROOF of the diagonals congruent:Take a rectangle ABCD with diagonals AC and BD.Using Pythagoras on the triangles ACD and BCD:AC² = AD² + CD²BD² = BC² + CD²But as ABCD is a rectangle AD = BC since they are opposite and parallel; thus:AC² = AD² + CD² = BC² + CD² = BD²Thus, as AC and BD are the diagonals, they are equal.Therefore the diagonals of a rectangle are congruent.
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