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Yes, the expression AC + AD + BC + BD can be factored as (A + C)(B + D). This is evident by applying the distributive property, where expanding (A + C)(B + D) yields AB + AD + BC + CD. The terms AC and BD are not present, so the expression can be expressed in a different form, but the original expression itself represents a different factoring structure.
What else can I help you with?
How is a plus b over a minus b equals c plus d over c minus d?
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
Does distributive property apply to complex numbers?
Yes, for example (a + bi)(c + di) = ac + adi + bic + bidi, and commutative property works as well --> ac + adi + bci + bdi² --> ac + (ad + bc)i + bd(-1) = (ac - bd) + (ad + bc)i
What is 15ac plus 20bc plus 6ad plus 8bd?
15 ac + 20 bc + 6 ad + 8 bd =3a (5c + 2d) + 4b (5c + 2d) =(3a + 4b) (5c + 2d)
What kind of reaction is a plus bc b plus ac?
associative? single replacement
What does AC and AD stand for in calendar terms?
Are you asking what BC and AD are, they are Before Christand the Latin phrase Anno Domini meaning Year of the Lord, never heard of AC on calendars.
How is a plus b over a minus b equals c plus d over c minus d?
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
If ab plus bc equals ac then ac equals ab plus bc?
yes because ab plus bc is ac
Factor ac plus ad plus bc plus bd?
a(c+d)+b(c+d)=(a+b)(c+d)
How to calculate years using bc from ac?
Take the BC year and add it to the AD year with present year and bc & ad
What type of reaction is the generic equation A plus BC AC plus B?
A+BC+AC+B=A+BC+AC+B unless any of these variables has an assigned value.
Is AC plus BC could equal 15?
It is possible, depending on what on earth AC and BC are!
What kind of reaction is A plus BC æ B plus AC?
associative? single replacement
Does distributive property apply to complex numbers?
Yes, for example (a + bi)(c + di) = ac + adi + bic + bidi, and commutative property works as well --> ac + adi + bci + bdi² --> ac + (ad + bc)i + bd(-1) = (ac - bd) + (ad + bc)i
What is 15ac plus 20bc plus 6ad plus 8bd?
15 ac + 20 bc + 6 ad + 8 bd =3a (5c + 2d) + 4b (5c + 2d) =(3a + 4b) (5c + 2d)
How do you factor ab plus bc plus b2 plus ac?
(a + b)(b + c)
AC plus BC could equal 15?
never A+ :))
What kind of reaction is a plus bc b plus ac?
associative? single replacement
