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∙ 11y agox+y=251/x + 1/y=.25
Solve for y in both:
y=25-x
1/y=.25-1/x, so y=1/(.25-1/x)
Use substitution:
25-x=1/(.25-1/x)
(25-x)(.25-1/x)=1
6.25-25/x -.25x+1=1
Combine like terms:
-.25x+6.25-25/x=0
Multiply everything by x:
-.25x^2 +6.25x-25=0
Multiply everything by negative 1:
.25x^2-6.25x+25=0
Multiply everything by 4:
x^2 -25x +100=0
Use the quadratic formula:
x=[25±√(25^2 -4(1)(100)]/2(1)
x=[25±√(625-400)]/2
x=[25±√225]/2
x=(25±15)/2
x=40/2 or x=10/2
x=20 or x=5
Plug these values into the original equation, and you will see that y also = 20 or 5.
So, the two pairs of numbers that satisfy the original equation are:
x=5, y=20; and x=20, y=5
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∙ 11y agoyes, it is rational because it isnt neverending. irrational numbers are neverending like pi which is 3.14-----------------------------------. it basically never ends. rationals such as 25 over 100 end if you divide 100 into 25. sources: my algebra book
There is a formula to calculate this sum. It is, S = ½n(n + 1) In this question, n = 25 so the sum of the numbers from 1-25 is, ½ x 25 x 26 = 325
There are 12 even numbers between 2 and 24 inclusive.The sum is 154.
The numbers are: 6 and 19
The numbers are 25 and 15
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
The sum of the first 25 prime numbers is 1,060.
If the sum of 2 numbers is 25 and their product is 156, the numbers are 12 and 13.
If the sum of 2 numbers is 25 and their product is 156, the 2 numbers would be 12 and 13.
The sum of the first 25 prime numbers is 1,060.
yes, it is rational because it isnt neverending. irrational numbers are neverending like pi which is 3.14-----------------------------------. it basically never ends. rationals such as 25 over 100 end if you divide 100 into 25. sources: my algebra book
They are: .025, 0.25, 2.5 and 25
025 is the same as 25 which is greater than 5
There is a formula to calculate this sum. It is, S = ½n(n + 1) In this question, n = 25 so the sum of the numbers from 1-25 is, ½ x 25 x 26 = 325
23 + 2 = 25
The sum of the first 25 numbers is 25*26/2 = 325 So the sum of the first 25 multiples of 12 is 325*12 = 3900
625