Sum of first 25 multiples of 44+8+12....100taking 4 common4(1+2+3+4....+25) = 4*325 =1300
5 + 10 + 15 + 20 + 25 + 30 + 35 = 140 ANSWER = 140
20 + 25 + 30 = 75
30, 60, 90, 120, 150
12, 24, and 36
Sum of first 25 multiples of 44+8+12....100taking 4 common4(1+2+3+4....+25) = 4*325 =1300
975
5 + 10 + 15 + 20 + 25 + 30 + 35 = 140 ANSWER = 140
Why, that's just 6 times the sum of the numbers from 1 to 50 !The sum of the numbers from 1 to 50 is:1 + 50 = 512 + 49 = 513 + 48 = 514 + 47 = 515 + 46 = 51...etc. There are 25 pairs, and each pair sums to 51. So the sum of 1 ... 50 is (25 x 51) = 1,275.The sum of the first 50 multiples of 6 is (1,275 x 6) = 7,650.
There are 12 even numbers between 2 and 24 inclusive.The sum is 154.
2100, 4200, 6300, 8400
25 and 50
20 + 25 + 30 = 75
30, 60, 90, 120, 150
12, 24, and 36
The highest power of 25 that divides the product of the first 100 multiples of 5 is 50. This is because for each multiple of 25, we have an extra factor of 25. Since there are 4 multiples of 25 in the first 100 multiples of 5, we have a total of 50 factors of 25.
The sum of the first 25 prime numbers is 1,060.