LCM(a2b5, a3b3) The LCM of both numbers HAS to have the largest coefficient of both variables. For a, it's a3, and for b it is b5. So the LCM is a3b5.
a5+b5 = (a+b) (a4-a3b+a2b2-ab3+b4)
54
a3+b3=(a+b)3-3a2b-3ab2
a3+b3
(a+b)3=a3+b3+3ab(a+b) a3+b3=(a+b)3-3ab(a+b) a3+b3=(a+b)(a2-ab+b2)
LCM(a2b5, a3b3) The LCM of both numbers HAS to have the largest coefficient of both variables. For a, it's a3, and for b it is b5. So the LCM is a3b5.
a5+b5 = (a+b) (a4-a3b+a2b2-ab3+b4)
54
(a + b)3 = a3 + 3a2b + 3ab2 + b3
a3+b3=(a+b)3-3a2b-3ab2
a3+b3
This is the formula: (a3)+(b3)=(a+b)(a2-ab+b2)
(a3 + b3)/(a + b) = (a + b)*(a2 - ab + b2)/(a + b) = (a2 - ab + b2)
10
(a + b+ c)3 = a3 + b3 + c3 + 3a2b + 3ab2 + 3b2c + 3bc2 + 3c2a + 3ca2 + 6abc
the answer to factorising (a x a3 + 2ab + b2) would be (a4+2ab+b2)