1/18
W/4 mph
To find the cyclist's average speed, divide the total distance traveled by the total time taken. In this case, the cyclist traveled 72 miles in 4 hours. Therefore, the average speed is 72 miles ÷ 4 hours = 18 miles per hour.
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? A. 2 hoursB. 4 ½ hoursC. 5 ¾ hoursD. 6 hoursE. 7 ½ hours AnswerThe distance the 1st cyclist travels is 6(3+t) miles, andthe distance the 2nd cyclist travles is 10t miles...where t=the number of hours since cyclist #2 starts.Now solve: 6(3+t)=10t ==> 18+6t=10t ==> 18=4t ==> t=4.5 hrs==> 4.5 hours = 4 hrs 30 minutes
The average speed for the entire trip is 9mph.
1/18
W/4 mph
To find the average speed of a cyclist, divide the total distance traveled by the total time taken to travel that distance. For example, if a cyclist covers 30 miles in 2 hours, the average speed would be 15 miles per hour (30 miles divided by 2 hours).
To find the average speed of a cyclist, you would divide the total distance traveled by the total time taken to cover that distance. For example, if a cyclist rides 20 miles in 2 hours, the average speed would be 10 miles per hour (20 miles / 2 hours = 10 mph).
To find the cyclist's average speed, divide the total distance traveled by the total time taken. In this case, the cyclist traveled 72 miles in 4 hours. Therefore, the average speed is 72 miles ÷ 4 hours = 18 miles per hour.
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? A. 2 hoursB. 4 ½ hoursC. 5 ¾ hoursD. 6 hoursE. 7 ½ hours AnswerThe distance the 1st cyclist travels is 6(3+t) miles, andthe distance the 2nd cyclist travles is 10t miles...where t=the number of hours since cyclist #2 starts.Now solve: 6(3+t)=10t ==> 18+6t=10t ==> 18=4t ==> t=4.5 hrs==> 4.5 hours = 4 hrs 30 minutes
Assuming you want to know how long before the second catches up with the first: After 3 hours the first cyclist has travelled 3 x 6 = 18 miles Second cyclist is travelling at 10mph, so in every hour he does 10-6 = 4 miles more. So to catch up the 18 miles between the two will take 18 / 4 = 4.5 hours = 4 hrs 30 mins
The average speed for the entire trip is 9mph.
The average speed is 8 and 8/9 mph.
1 and a half hours
Velocity = distance / time Given d = 72 miles ; t = 4 hour V = 72 miles / 4 hour = 18 miles per hour
9 mph and 18 mph