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Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.
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Fayge is the character the Shmuel marries. She follows them through out their whole journey, with her father, Rabi Boruch. (sp?)
In multiplication PEMDAS P= Pretty E= Elizabeth M= Marries D= Dummy A= Adam S= Sandler
Michal is mentioned for the first time I Samuel 18:20. David marries her in I Samuel 18:26.
All of their children are expected to be heterozygous for the trait (Tt), which means they would be tall (dominant phenotype). The recessive trait for being short would only manifest if both copies of the gene were recessive.
Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.
If the man has dystonia and the woman does not, the man would have a genotype of heterozygous for the mutation (Dd) while the woman would have a genotype of homozygous normal (dd). The possible genotypes for their child would be Dd (heterozygous carrier) or dd (homozygous normal).
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50% of their children are expected to have a widow's peak. When a heterozygous male (Ww) with a widow's peak gene marries a female with a straight hairline (ww), their offspring have a 50% chance of inheriting the widow's peak gene from the father.
Do a punnet square.I am really bad at them, otherwise I would be more helpful. Got a C in biology.
The children will have type AB
Horse marries horse.
No god is marries yet
genotype means genetic make up. it can give the information about the parents wether they were homozygous or heterzygousAnswer (Improved)A genotypic ratio is the proportion of genotypes found in individuals after a cross. For example, consider a cross between two heterozygous individuals for trait A: Aa X AaThe result is a 1:2:1 ratio for the genotypes AA, Aa, and AA respectively. Put another way, if the parents had 100 offspring, 25 would be expected to have the genotype AA, 50 the genotype Aa and 25 the genotype AA.This is hard Good Luck
Sonic the Hedgehog marries Sally.