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How many combinations are there for the numbers 1-56 with 9 numbers?
Assuming 9 numbers chosen from 56, with no repetition allowed, there are 7575968400 possible combinations.
How many different sets of 2 books can be chosen from a set of 6 different books?
There are 30 different combinations if the order in which the books were chosen counts, so a set of book A and book B is considered different from a set of book B and book A. There are 15 different combinations if it does not matter in which order the books were chosen, so a set of book A and book B is considered the same as a set of book B and book A.
A bin contains 3 red balls 2 green balls and 1 blue ball two balls are randomly chosen from a bin how many different color combinations are possible?
6 Is how many different combinations there are
How many possible combinations using 4 numbers?
The number of possible combinations using 4 distinct numbers depends on whether the order matters and whether repetitions are allowed. If order does not matter and repetitions are not allowed, the number of combinations of 4 numbers chosen from a larger set can be calculated using the combination formula (C(n, r) = \frac{n!}{r!(n-r)!}), where (n) is the total number of numbers available. If order matters, you would use permutations instead. Please specify if you need combinations with or without repetitions and whether order matters for a more precise answer.
How many combinations of 3 out of ten numbers?
There are 10 x 9 x 8 ways to select 3 numbers from 10 in order (permutations of 3 numbers from 10), but as want the number of combinations, the order doesn't matter, so need to divide by the number of ways 3 numbers can be ordered which is 3 x 2 x 1. Thus: combinations(3 from 10) = (10 x 9 x 8)/(3 x 2 x 1) = 120. There are formulae for the number of permutations and combinations of r items chosen from a set of n items: Permutations: nPr = n!/(n-r)! Combinations: nCr = n!/(n-r)!r! Where n! means "n factorial" which is the product of n with all numbers less than it to 1, ie n! = n x (n-1) x ... x 2 x 1 The combinations nCr is also written as a vector with n over r, as in (nr), but it is difficult to show the n exactly over the r as it should be (with the characters available) so I use the nCr format which is found on scientific calculators.
How many combinations are there for the numbers 1-56 with 9 numbers?
Assuming 9 numbers chosen from 56, with no repetition allowed, there are 7575968400 possible combinations.
How many ways can a group of 7 people be chosen from a class of 15?
It is: 15C7 = 6435 combinations
How many different combinations of 4 books can be chosen from 6 books?
The number of 4 different book combinations you can choose from 6 books is;6C4 =6!/[4!(6-4)!] =15 combinations of 4 different books.
How many different sets of 2 books can be chosen from a set of 6 different books?
There are 30 different combinations if the order in which the books were chosen counts, so a set of book A and book B is considered different from a set of book B and book A. There are 15 different combinations if it does not matter in which order the books were chosen, so a set of book A and book B is considered the same as a set of book B and book A.
A bin contains 3 red balls 2 green balls and 1 blue ball two balls are randomly chosen from a bin how many different color combinations are possible?
6 Is how many different combinations there are
How many license plate combinations from 3 digits followed by 3 letters?
There are 26 different letters that can be chosen for each letter. There are 10 different numbers that can be chosen for each number. Since each of the numbers/digits that can be chosen for each of the six "spots" are independent events, we can multiply these combinations using the multiplicative rule of probability.combinations = (# of different digits) * (# of different digits) * (# of different digits) * (# of different letters) * (# of different letters) * (# of different letters) = 10 * 10 * 10 * 26 * 26 * 26 = 103 * 263 = 1000 * 17576 = 17,576,000 different combinations.
Who built the terracotta site?
The Terracotta Warriors Site was built by Ancient Chinese slaves and also by the King's workers ordered by him and chosen by him.
How many combinations of 6 are there for numbers 1-36?
Oh honey, you're asking about combinations now? Buckle up, buttercup. There are a whopping 1,947,792 combinations of 6 numbers chosen from 1 to 36. That's a whole lot of possibilities, but hey, someone's gotta win the lottery, right?
Who built the terracotta warriors site?
The Terracotta Warriors Site was built by Ancient Chinese slaves and also by the King's workers ordered by him and chosen by him.
How many combinations of 3 out of ten numbers?
There are 10 x 9 x 8 ways to select 3 numbers from 10 in order (permutations of 3 numbers from 10), but as want the number of combinations, the order doesn't matter, so need to divide by the number of ways 3 numbers can be ordered which is 3 x 2 x 1. Thus: combinations(3 from 10) = (10 x 9 x 8)/(3 x 2 x 1) = 120. There are formulae for the number of permutations and combinations of r items chosen from a set of n items: Permutations: nPr = n!/(n-r)! Combinations: nCr = n!/(n-r)!r! Where n! means "n factorial" which is the product of n with all numbers less than it to 1, ie n! = n x (n-1) x ... x 2 x 1 The combinations nCr is also written as a vector with n over r, as in (nr), but it is difficult to show the n exactly over the r as it should be (with the characters available) so I use the nCr format which is found on scientific calculators.
How many 7 number combinations from 8 numbers?
To calculate the number of 7-number combinations from 8 numbers, you can use the combination formula, which is nCr = n! / r!(n-r)!. In this case, n = 8 (total numbers) and r = 7 (numbers chosen). Plugging these values into the formula, you get 8C7 = 8! / 7!(8-7)! = 8 ways. Therefore, there are 8 different combinations of 7 numbers that can be chosen from a set of 8 numbers.
How many possible combinations of 1 hat 1 pair of sunglasses can be made with 5 hats and 4 pairs of sunglasses?
You can choose 5 different hats and for each of them 4 different sunglasses can be chosen, giving 5 x 4 = 20 different combinations.
