Oh, dude, .31 of an inch is like almost a third of an inch. It's like if you have a ruler, and you're trying to measure something super precise, but not too precise, you know? So yeah, it's just a smidge over a quarter of an inch.
16 to 26 (+10) 26 to 21 (-5) 21 to 31 (+10) 31 (-5) = 26 26
The mathematical statement 31 plus 21 equals 52 as a total.
The statement 10 plus 21 equals 31 in total. It can also be written as 10 + 21 = 31.
31
28 inch square
The area of a rectangle of length 12.3 and width 31 is 12.3 X 31 = 381.3, the perimeter of the same rectangle is 2(12.3+31) = 86.6.
Yes it can. If it is a rectangle then the sides would be (7+√31)x(7-√31).
the width equals 14 cm. and the length equals 31 cm.
We don't know. The perimeter doesn't uniquely define the dimensions. It could be: 1 x 35 2 x 34 3 x 33 4 x 32 5 x 31 10 x 26 15 x 21 15.39 x 20.61 . . etc. All of these rectangles have a perimeter of 72.
31 cm
Let's call the length L and the width W. The width is 5 less than half of the length, so W = (1/2)L - 5. The length is 31, so W = (1/2)(31)-5, which is 10.5. So the length is 31 cm and the width is 10.5 cm. The perimeter is 2 lengths and 2 widths, so the perimeter equals 2L + 2W. In this case, it is 2(31) + 2(10.5) which is 83 cm.
Amazing Stories - 1985 The 21-Inch Sun - 2.15 was released on: USA: 2 February 1987 UK: 31 July 1994
31 centimeters
All you do is add the sides up for the perimeter. 12 + 10 + 9 = 31
Amazing Stories - 1985 The 21-Inch Sun 2-15 was released on: USA: 2 February 1987 UK: 31 July 1994
You would require a minimum of 31, but that is only if the area is a rectangle with sides of specific lengths or if you are happy to use up all off-cuts as mosaic. For a rectangle of other sizes, or a non-rectangular area, you will require more: how many more depends on the precise shape and your tiling skills.