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If a rectangle is 54sqft the length of the rectangle is 15ft more than the width what is the length and width in feet?
area (A) = length (L) x width (W) = 54
L = W+15
so.....
(W + 15) x W = 54
then
W^2 + 15W = 54
putting it in a form (aX^2 + bX + C = 0) so that a quadratic formula (look it up on Widipedia) can be used to solve it:
W^2 + 15W - 54 = 0
a=1, b = 15, c = -54
Solving give us W = 3, which means L = 18
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