63
a rectangle had a perimeter of 48 and the longest side is 15 find the lenght of a shorter side
The area of a rectangle of sides 9cm and 10cm is:9cm x 10cm = 90cm2This is equivalent to 0.009m2
9cm obv
Area = 0.5*(9 + 3)*11 = 0.5*12*11 = 66 sq cm
15 cm Solved through Pythagoras' theorem.
12 Pythagorean theorem
9cm
63
18 square cm
a rectangle had a perimeter of 48 and the longest side is 15 find the lenght of a shorter side
Perimeter = 6cm + 6cm + 9cm + 9cm = 30cm
To find the area (A) of any rectangle, we multiply the length (l) by the width (w). In the case of a rectangle that is 11 cm by 9 cm, we do this:Arectangle = l x w = 11 cm x 9 cm = 99 cm2or 99 square centimeters.
11cm
It is: 9*3 = 27 square cm
The area of rectangle is : 18.0
The area of a rectangle of sides 9cm and 10cm is:9cm x 10cm = 90cm2This is equivalent to 0.009m2