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A standard six-sided die has three odd numbers: 1, 3, and 5. Therefore, the probability of rolling an odd number is the number of favorable outcomes (3) divided by the total number of outcomes (6). This gives a probability of ( \frac{3}{6} ), which simplifies to ( \frac{1}{2} ). Thus, the probability of rolling an odd number is ( 0.5 ) or 50%.
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A dice is tossed thrice find the probability of getting an odd number at least once?
To find the probability of getting an odd number at least once when a die is tossed thrice, we can use the complementary approach. The probability of not getting an odd number (i.e., getting an even number) in a single toss is ( \frac{3}{6} = \frac{1}{2} ). Therefore, the probability of getting an even number in all three tosses is ( \left(\frac{1}{2}\right)^3 = \frac{1}{8} ). Thus, the probability of getting an odd number at least once is ( 1 - \frac{1}{8} = \frac{7}{8} ).
A fair coin is tossed three times find the probability of getting exactly 2 heads?
3 out of 8
A fair coin is tossed 5 times What is the probability of exactly 1 head?
First, you find the probability of picking 1 in 5 disregarding order (combination). 5 C 1 = 5/1 = 5 Then you divide that by the possible number of outcomes which is 25. 5/ 2^5= .0195
A single die is toss Find the probability of getting a 5?
A 6-sided die has 6 possible outcomes. If each of the sides has a different number from 1 to 6, then the probability of getting any one number is 1/6 or 16.67%.
How do you find probability?
To find probability in a question you first have to determine the whole number which from the question which will be the denominator next determine the numerator from the question then put that number in the fraction.To find probability u have to look at the possibilities which will be the denominator the find the successes which will be the numerator
A dice is tossed thrice find the probability of getting an odd number at least once?
To find the probability of getting an odd number at least once when a die is tossed thrice, we can use the complementary approach. The probability of not getting an odd number (i.e., getting an even number) in a single toss is ( \frac{3}{6} = \frac{1}{2} ). Therefore, the probability of getting an even number in all three tosses is ( \left(\frac{1}{2}\right)^3 = \frac{1}{8} ). Thus, the probability of getting an odd number at least once is ( 1 - \frac{1}{8} = \frac{7}{8} ).
A die is tossed. Find the odds against rolling a number greater than 1.?
The probability of rolling a number greater than 1 is 5/6.
When a penny and a nickel are tossed. find the probability that the penny shows heads given that the nickel shows heads?
The probability is 0.5
Find the probability of getting a total of 8 in a pair of dice is tossed?
5/36 or 13.9%.
A fair coin is tossed three times find the probability of getting exactly 2 heads?
3 out of 8
A pair of fair dice is tossed 3 times find the probability a seven appears 3 times?
The probability that the sum is seven all three times is 1/216.
How do you find the probability of a random point being chosen in a shaded region in a circle?
The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.
A single die is rolled one time Find the probability of rolling a number that is odd and less than 4?
1
A coin is tossed five times find the probability of getting exactly three heads?
Since a coin has two sides and it was tossed 5 times, there are 32 possible combinations of results. The probability of getting heads three times in 5 tries is 10/32. This is 5/16.
A coin is tossed and then a die is rolled Find the probability of getting a 5 on the die given that the coin landed tails up?
9/2
What is this answer a coin is tossed and a number cube is rolled Find P heads then greater than 4?
With one toss of a coin, there can be at most 1 head. So the probability of 4 or more heads is very definitely 0.
A fair coin is tossed 5 times What is the probability of exactly 1 head?
First, you find the probability of picking 1 in 5 disregarding order (combination). 5 C 1 = 5/1 = 5 Then you divide that by the possible number of outcomes which is 25. 5/ 2^5= .0195
