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There are 34 ie 81 possibilities: B appears exactly twice in 18 of these: AABB, ABAB, ABBA, ABBC,ABCB, ACBB, BABA, BABC, BBAA, BBAC, BCAB, BCCB, CABB,CBAB, CBBA, CBBC, CCBA and CCBB.

B comes up exactly twice in 18 of the 81 possibilities so probability = 18/81 = 0.22 or 22.2%

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Q: If a spinner with 3 equal sections labeled A B and C is spun 4 times what is the probability of spinning B exactly 2 times?
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