There are 34 ie 81 possibilities: B appears exactly twice in 18 of these: AABB, ABAB, ABBA, ABBC,ABCB, ACBB, BABA, BABC, BBAA, BBAC, BCAB, BCCB, CABB,CBAB, CBBA, CBBC, CCBA and CCBB.
B comes up exactly twice in 18 of the 81 possibilities so probability = 18/81 = 0.22 or 22.2%
0.75%
To find the probability of the pointer landing on 3, you need to know the total number of equal sections on the spinner. If the spinner has ( n ) sections, and one of them is labeled 3, the probability is calculated as ( \frac{1}{n} ). For example, if there are 8 sections, the probability would be ( \frac{1}{8} ). Without knowing the total number of sections, the exact probability cannot be determined.
the probability is 4 out of 6
50
The probability of landing on A in one spin is ( \frac{1}{4} ). To find the probability of landing on A twice in a row, you multiply the probabilities of each independent event: ( \frac{1}{4} \times \frac{1}{4} = \frac{1}{16} ). Therefore, the probability of landing on A twice in a row is ( \frac{1}{16} ).
0.75%
To find the probability of the pointer landing on 3, you need to know the total number of equal sections on the spinner. If the spinner has ( n ) sections, and one of them is labeled 3, the probability is calculated as ( \frac{1}{n} ). For example, if there are 8 sections, the probability would be ( \frac{1}{8} ). Without knowing the total number of sections, the exact probability cannot be determined.
To calculate the probability of spinning a multiple of 3 on a spinner labeled 1 through 10, we first determine the total number of favorable outcomes. The multiples of 3 between 1 and 10 are 3, 6, and 9. Therefore, there are 3 favorable outcomes. Since there are a total of 10 equally likely outcomes on the spinner, the probability of spinning a multiple of 3 is 3/10 or 0.3.
the probability is 4 out of 6
50
The probability of landing on A in one spin is ( \frac{1}{4} ). To find the probability of landing on A twice in a row, you multiply the probabilities of each independent event: ( \frac{1}{4} \times \frac{1}{4} = \frac{1}{16} ). Therefore, the probability of landing on A twice in a row is ( \frac{1}{16} ).
To set up a spinning wheel for a game or activity, you will need a wheel with sections labeled with different prizes or outcomes, a sturdy base to hold the wheel upright, and a mechanism to spin the wheel such as a peg or handle. Simply assemble the wheel on the base, ensure it spins freely, and then you're ready to play!
What_is_the_probability_of_spinning_a_free_on_one_spin_and_an_s_on_your_second_if_you_have_a_spinner_with_1_space_labeled_free_and_the_remaining_11_mississippi_with_one_letter_in_each.So, you would multiply 1/12 times 4/12 to get 4/144 or 1/36
There is 1 section numbered 1, 5 sections numbered 2 and 2 sections numbered 3.
1
It is 2/3.
The probability of any event is always a number from 0 to 1, inclusive. It can never be 12.