To calculate the probability of spinning a multiple of 3 on a spinner labeled 1 through 10, we first determine the total number of favorable outcomes. The multiples of 3 between 1 and 10 are 3, 6, and 9. Therefore, there are 3 favorable outcomes. Since there are a total of 10 equally likely outcomes on the spinner, the probability of spinning a multiple of 3 is 3/10 or 0.3.
The probability is 5/9.
The probability is 3/7.
1
Total number of possible stops = 8Number of successful stops = 2 (stops on 3 or on 6 are successful)Probability = 2/8 = 25%
The probability that the spinner will land on six depends on how many numbers are on the spinner. If the spinner is only 1 through 6, then there is a 16.67% probability that the spinner will land on six with each spin.
The probability is 5/9.
The probability is 3/7.
17 out of 21
6-52
1
Total number of possible stops = 8Number of successful stops = 2 (stops on 3 or on 6 are successful)Probability = 2/8 = 25%
The answer depends on the numbers on the spinner.The answer depends on the numbers on the spinner.The answer depends on the numbers on the spinner.The answer depends on the numbers on the spinner.
The probability that the spinner will land on six depends on how many numbers are on the spinner. If the spinner is only 1 through 6, then there is a 16.67% probability that the spinner will land on six with each spin.
In a spinner numbered from 1 to 10, the multiples of 5 are 5 and 10. There are 2 favorable outcomes (5 and 10) out of a total of 10 possible outcomes. Therefore, the probability of landing on a multiple of 5 is 2 out of 10, which simplifies to 1/5 or 0.2. Thus, the probability is 20%.
The spinner has five equal sections marked 1 through 5, with the even numbers being 2 and 4. There are 2 favorable outcomes (landing on an even number) out of a total of 5 possible outcomes. Therefore, the probability of landing on an even number is ( \frac{2}{5} ) or 40%.
The probability is one in four, or 25%.
1/2