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What determines the area of a quadrilateral within a square?
The only thing that can be said is that the quadrilateral will have an area that is smaller than the square. The exact value depends on the location of the vertices.
What is the area of a triangle with vertices at -3 7 and 2 19 and 10 7?
By plotting the given vertices and then joining them together on the Cartesian plane the shape of a isosceles triangle will be formed with an area of 78 square units.
What is the area of a square whose vertices have the coordinates (36)(31)(-21)(-26)?
To find the area of a square, we need the length of one side. The given coordinates appear to be the x-coordinates of the vertices, but without the corresponding y-coordinates, we cannot determine the vertices' positions or calculate the side length. Assuming the vertices were intended to be (36, 31), (-21, 31), (-21, -26), and (36, -26), the side length would be the difference in the x-coordinates, which is 36 - (-21) = 57. Thus, the area would be (57^2 = 3249) square units.
What are the interior angles and area of a triangle with vertices at 5 9 and 14 -3 and 2 3 on the Cartesian plane?
Plotting the given vertices on the Cartesian plane results in a right angle triangle with angles of 90 degrees, 26.565 degrees and 63.435 degrees including an area of 45 square units.
What is the area of a square and its 4th vertex when its other vertices are at -5 4 and -1 -2 and 5 2?
Plotted on the Cartesian plane its 4th vertex is at (1, 8) and it has sides of 2 times square root of 13 which gives it an area of 52 square units.
What is the area of a square with vertices of (36) (31) (-2-1) (-2 6)?
The shape described by those vertices is not a square.
What is the area of (36) (9 3) (5 3)?
Assuming that these are coordinates of the vertices, the area is 6 square units.
What determines the area of a quadrilateral within a square?
The only thing that can be said is that the quadrilateral will have an area that is smaller than the square. The exact value depends on the location of the vertices.
How do I calculate the area of a square that's inside of a square?
With the available information all that can be said is that the area of the second square will be less than that of the first. The question cannot be answered in any meaningful way without further information. For example, do the vertices of the second square lie on the sides of the first? How far from the vertices of the first? What angle is the second square rotated through?
What is the area of a triangle with vertices at -3 7 and 2 19 and 10 7?
By plotting the given vertices and then joining them together on the Cartesian plane the shape of a isosceles triangle will be formed with an area of 78 square units.
What is the area of a rectangle with vertices at (73) (123) (1211) (711)?
If you mean vertices of: (7, 3) (12, 3) (12, 11) (7, 11) then the area works out as 5 times 8 = 40 square units
What is the area of a square whose vertices have the coordinates (36)(31)(-21)(-26)?
To find the area of a square, we need the length of one side. The given coordinates appear to be the x-coordinates of the vertices, but without the corresponding y-coordinates, we cannot determine the vertices' positions or calculate the side length. Assuming the vertices were intended to be (36, 31), (-21, 31), (-21, -26), and (36, -26), the side length would be the difference in the x-coordinates, which is 36 - (-21) = 57. Thus, the area would be (57^2 = 3249) square units.
What two consecutive does the side length of a square of an area of 90 square inches fall between?
9 inches and 10 inches.
What is the area of a triangle with vertices at (0 -2) (8 -2) (9 1)?
If the vertices are at (0, -2) (8, -2) and (9, 1) on the Cartesian plane plane then by using the distance formulae and trigonometry the area of the triangle works out as 12 square units.
What are the interior angles and area of a triangle with vertices at 5 9 and 14 -3 and 2 3 on the Cartesian plane?
Plotting the given vertices on the Cartesian plane results in a right angle triangle with angles of 90 degrees, 26.565 degrees and 63.435 degrees including an area of 45 square units.
What is the area of a rectangle with vertices at (4 3) (11 3) (11 9) and (4 9)?
The area of the rectangle works out as 7 times 6 = 42 square units
What vertices of a polygon are located at 2-1 6-1 5-4 and 1-4 what is the area of the polygon?
+/- the square root of 3
