The sides of a triangle always equal to 180 so 63+54 = 117 and 180 - 117 = 63. The answer is 63. Or, an isosceles triangle has 2 sides of the same length, so you know it would either be 54 or 63
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It is an isosceles triangle and the 3rd angle is 72 degrees.
63 degrees
An obtuse triangle.
This is how you find the area of a regular pentagon: Break it into five isosceles triangles by drawing lines from the middle of it to each vertex. Then, draw a line connecting the middle to the midpoint of a side. You can call that line the apothem. The apothem should break up one of the triangles into two smaller congruent right triangles. You can know the degrees in the triangle by dividing the central angle of 360 by 10, (dividing it by 10 because your smallest triangle you're going to use is 1/10th of the whole pentagon) So now you know the unknown angle towards the top of the smallest triangle is 36, do the subtraction so the unknown angle towards the bottom is 54. Now trig it out! SOH-CAH-TOA shows that tan(54)=(a/s). A being the apothem and s being the side length of the smallest triangle, which is half a side length. Now that you know the lengths of the smallest triangle, find the area of that. That triangle is replicated 10 times in the pentagon, so multiply it by 10.
40" x 40" x 54" (or 56")
Since you know one base angle is 54 then the other base angle is also 54 making a total of 108. Since a triangle is 180, your vertex angle is 72.
In an isosceles triangle, two angles are equal. Since the angles provided are 54 degrees and 63 degrees, the equal angles must be 54 degrees. The sum of the angles in any triangle is 180 degrees. Thus, the measure of the third angle is calculated as follows: 180 - 54 - 54 = 72 degrees.
The total internal angles of a triangle always equal 180 degrees. Therefore, the third angle of this triangle must be 180 - 54 - 63 = 63. Since this value is the same as one of the stated sides, the triangle is indeed isosceles.
It is an isosceles triangle and the 3rd angle is 72 degrees.
If the two base angles of an isosceles triangle are both 27 degrees then the vertex angle is 126 degrees because the sum of a triangles angles is always 180 degrees, 27 and 27 is 54, 180-54 is 126.
63 degrees
3 x 18 = 54
Since there is no triangle "below", all that can be said is that EF - if it is the third side of the triangle - is any length in the interval (24, 54).
let the vertex angle be x degrees, then the base angle is x + 9 degrees. Since in a triangle the sum of the angle is 180 degrees, and the base angles in an isosceles triangle are congruent, we have: x + 2(x + 9) = 180 x + 2x + 18 = 180 3x + 18 = 180 subtract 18 to both sides 3x = 162 divide by 3 to both sides x = 54 Thus the vertex angle is 54 degrees.
The sum of the 2 smallest sides of a triangle must be greater than the length of its longest side
No. A triangle has 180 degrees in it. A right triangle has an angle of 90 degrees. That leaves the other two angles to total 90 as well. 38+54=92 which would make the triangle equal 182 degrees. this is not possible.
An obtuse triangle.