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What does vt mean in the vertical motion formula?
it means initial upwards height times time in seconds
Question-1 A body is thrown vertically upwards The distance st above the ground after t seconds is given by st 20t-5t2 meters?
The equation for vertical motion is y = v0t + .5at2. y is vertical displacement v0 is initial vertical velocity a is acceleration (in meters, normal gravitational acceleration is about -9.8 m/s/s, assuming positive y is upward displacement and negative y is downward displacement)
When A baseball is hit straight up at an initial velocity of 100 ms how long will it take to hit the ground?
The baseball will travel upwards until its velocity is zero and then fall back down again. The acceleration of the baseball is the constant acceleration due to gravity acting in a downwards direction. The time taken to fall back down will be the same as the time to climb, thus the total time is twice the climb time. Use Netwon's equations of motion and ignore air resistance, the time to the top of the climb is: v = u + at → t = v - u/a v = final velocity = 0 m/s at the top of the climb u = initial velocity = +100 m/s a = acceleration = -g m/s² t_top = 0 - (100 m/s) / (-g m/s²) = 100/g s → t_total = 2 × t_top = 2 × 100/g s = 200/g s ≈ 200/9.81 s ≈ 20.4 s
Is the total time of a ball thrown upwards is it equal to the total time of the downward velocity?
There's no such thing as "time of the downward velocity", but I think I get the sense of your question. If the effects of air resistance can be disregarded, then any object thrown upwards spends half of its time rising, and the identical amount of time falling back to the height of your hand when you let it go.
What is maximum velocity?
maximum velocity is the highest possibly speed an object can travel before the forces acting on it reach an equilibrium and it is no longer able to accelerate. For example a parachutist will fall and accelerate rapidly until the air resistance pushing upwards against her downward force becomes balanced and her speed is steady, its more commonly known as 'terminal velocity' not maximum.
How do you draw velocity time graph for a body thrown vertically upwards?
To draw a velocity-time graph for a body thrown vertically upwards, the initial velocity will be positive (upwards) and steadily decrease due to gravity until reaching zero at the peak. After the peak, the velocity becomes negative as the body falls back down. The graph will have a symmetrical shape with the velocity decreasing and then increasing back to the initial velocity.
Can the initial velocity be different if the final velocity is 0?
Yes, it is possible for the initial velocity to be different from zero when the final velocity is zero. For example, an object could be thrown upwards and come to a stop at its highest point, where the final velocity would be zero.
What makes a thrown upwards body to stop for some few seconds before desendeing down?
When a body is thrown upwards, it reaches its highest point where its velocity momentarily becomes zero before descending due to the gravitational force pulling it back down. This momentary stop at the highest point is due to the balance between the upward velocity from the initial throw and the downward pull of gravity.
What does vt mean in the vertical motion formula?
it means initial upwards height times time in seconds
A ball thrown vertically upward returns to the starting point in 8 seconds.find its initial velocity.?
The total time of flight for a ball thrown vertically upwards and returning to its starting point is twice the time taken to reach maximum height. Therefore, the time taken to reach maximum height is 4 seconds. Given that the acceleration due to gravity is -9.8 m/s^2, using the kinematic equation v = u + at, where v is the final velocity (0 m/s at maximum height), u is the initial velocity, a is the acceleration due to gravity, and t is the time, you can solve for the initial velocity. Substituting the values, u = 9.8 * 4 = 39.2 m/s. Therefore, the initial velocity of the ball thrown vertically upward is 39.2 m/s.
An object is thrown vertically upwards from the top of a tower of height 39.2 meters reach the ground in 4 secons Find the velocity with which it is thrown upwards?
To find the initial velocity with which the object is thrown upwards, we can use the kinematic equation for vertical motion: ( v = u + at ), where ( v ) is the final velocity (0 m/s at the highest point), ( u ) is the initial velocity, ( a ) is the acceleration due to gravity (-9.81 m/s²), and ( t ) is the time taken to reach the highest point (half the total time to reach the ground, so 2 seconds in this case). Rearranging the equation to solve for ( u ), we get ( u = v - at ). Plugging in the values, we get ( u = 0 - (-9.81 m/s² * 2 s) = 19.62 m/s ). Therefore, the object was thrown upwards with an initial velocity of 19.62 m/s.
How can one determine the vertical velocity of a projectile?
To determine the vertical velocity of a projectile, you can use the formula: vertical velocity initial vertical velocity (acceleration due to gravity x time). The initial vertical velocity is the speed at which the projectile is launched upwards or downwards. Acceleration due to gravity is typically -9.8 m/s2 (negative because it acts downwards). Time is the duration for which the projectile has been in motion. By plugging in these values, you can calculate the vertical velocity of the projectile.
How is gravity different for objects that freely fall down and those thrown upwards?
The gravity acting on a rising object and that on a falling object are the same when these objects are at the same height. What is different is that a rising object is decelerating by the force of gravity and the falling object is accelerating.
When object moves upwards what is the velocity and acceleration?
When an object is moving upwards, its velocity is directed upwards. If the object is near the Earth or any other planet, then its acceleration is directed downwards, which also means that its upward velocity is decreasing.
A arrow is shot strait up at an initial velocity of 250meters per seconds How long will it take to hit the ground?
To calculate the time it takes for the arrow to hit the ground, we need to consider the vertical motion of the arrow. The time taken for an object to fall back to the ground can be determined using the kinematic equation: h = (1/2)gt^2, where h is the initial height, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time. In this case, the initial velocity is upwards, so the initial height will be 0. Using the equation, we can determine the time it takes for the arrow to hit the ground.
A boy kicks a ball vertically upwards with an initial velocity of 12m/s. Calculate the time taken by the ball to reach the maximum hight and the maximum, height reached by the ball?
The time taken by the ball to reach the maximum height is 1 second. The maximum height reached by the ball is 36 meters.
What does a straight line sloping upwards on a position-time graph indicate about velocity?
A straight line sloping upwards on a position-time graph indicates that the object is moving with a constant positive velocity. The slope of the line represents the velocity of the object.
