Wiki User
∙ 14y agoIgnoring drag:
h=32.7*t-0.5*g*t2
Where g is about equal to 32.2 ft/sec2
Wiki User
∙ 14y agoit means initial upwards height times time in seconds
The equation for vertical motion is y = v0t + .5at2. y is vertical displacement v0 is initial vertical velocity a is acceleration (in meters, normal gravitational acceleration is about -9.8 m/s/s, assuming positive y is upward displacement and negative y is downward displacement)
The baseball will travel upwards until its velocity is zero and then fall back down again. The acceleration of the baseball is the constant acceleration due to gravity acting in a downwards direction. The time taken to fall back down will be the same as the time to climb, thus the total time is twice the climb time. Use Netwon's equations of motion and ignore air resistance, the time to the top of the climb is: v = u + at → t = v - u/a v = final velocity = 0 m/s at the top of the climb u = initial velocity = +100 m/s a = acceleration = -g m/s² t_top = 0 - (100 m/s) / (-g m/s²) = 100/g s → t_total = 2 × t_top = 2 × 100/g s = 200/g s ≈ 200/9.81 s ≈ 20.4 s
There's no such thing as "time of the downward velocity", but I think I get the sense of your question. If the effects of air resistance can be disregarded, then any object thrown upwards spends half of its time rising, and the identical amount of time falling back to the height of your hand when you let it go.
maximum velocity is the highest possibly speed an object can travel before the forces acting on it reach an equilibrium and it is no longer able to accelerate. For example a parachutist will fall and accelerate rapidly until the air resistance pushing upwards against her downward force becomes balanced and her speed is steady, its more commonly known as 'terminal velocity' not maximum.
To draw a velocity-time graph for a body thrown vertically upwards, the initial velocity will be positive (upwards) and steadily decrease due to gravity until reaching zero at the peak. After the peak, the velocity becomes negative as the body falls back down. The graph will have a symmetrical shape with the velocity decreasing and then increasing back to the initial velocity.
Yes, it is possible for the initial velocity to be different from zero when the final velocity is zero. For example, an object could be thrown upwards and come to a stop at its highest point, where the final velocity would be zero.
When a body is thrown upwards, it reaches its highest point where its velocity momentarily becomes zero before descending due to the gravitational force pulling it back down. This momentary stop at the highest point is due to the balance between the upward velocity from the initial throw and the downward pull of gravity.
it means initial upwards height times time in seconds
The total time of flight for a ball thrown vertically upwards and returning to its starting point is twice the time taken to reach maximum height. Therefore, the time taken to reach maximum height is 4 seconds. Given that the acceleration due to gravity is -9.8 m/s^2, using the kinematic equation v = u + at, where v is the final velocity (0 m/s at maximum height), u is the initial velocity, a is the acceleration due to gravity, and t is the time, you can solve for the initial velocity. Substituting the values, u = 9.8 * 4 = 39.2 m/s. Therefore, the initial velocity of the ball thrown vertically upward is 39.2 m/s.
The velocity with which the object is thrown upwards can be found using the equation v = u + at, where v is the final velocity (0 m/s at the top), u is the initial velocity, a is the acceleration due to gravity (-9.81 m/s^2), and t is the time taken to reach the ground (4 seconds). Rearranging the equation to solve for u, we have u = v - at. Plugging in the values, u = 0 - (-9.81 * 4) = 39.24 m/s. Therefore, the object is thrown upwards with a velocity of 39.24 m/s.
Gravity acts the same way on objects falling freely down and those thrown upwards. The difference lies in the initial velocity and direction of the objects. Objects thrown upwards have an initial velocity that opposes gravity, causing them to slow down and eventually fall back down due to gravity. Objects falling freely down have an initial velocity of zero and accelerate towards the ground due to gravity.
When an object moves upwards, its velocity is directed upwards if it is moving in the same direction as the motion. The acceleration, due to gravity, is directed downwards towards the center of the Earth. If the object is moving upwards against gravity, its acceleration is directed downwards but is a negative value.
To calculate the time it takes for the arrow to hit the ground, we need to consider the vertical motion of the arrow. The time taken for an object to fall back to the ground can be determined using the kinematic equation: h = (1/2)gt^2, where h is the initial height, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time. In this case, the initial velocity is upwards, so the initial height will be 0. Using the equation, we can determine the time it takes for the arrow to hit the ground.
The time taken by the ball to reach the maximum height is 1 second. The maximum height reached by the ball is 36 meters.
When an object is thrown upwards, the acceleration due to gravity pulls it downwards, opposite in direction to its initial velocity. This causes the object to eventually come to a stop and reverse its direction as it falls back down.
A straight line sloping upwards on a position-time graph indicates that the object is moving with a constant positive velocity. The slope of the line represents the velocity of the object.