Nice little problem !
Call the consecutive integers ' x ' and ' x+1 '.
The sum is [ x + 2(x+1) ] = A
x + 2x + 2 = A
3x + 2 = A
Subtract 2 from each side:
3x = A - 2
Divide each side by 3:
x = (A-2)/3 and that's the smaller of the two integers.
The larger one is (x+1) = (A+1)/3
-1
x+3 and x+4 would be consecutive integers.
There can be no such integers: a smaller integer cannot be 5 times the larger number.
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).
There are no such integers.
The larger integer is 30. The smaller is 28.
-1
x+3 and x+4 would be consecutive integers.
There can be no such integers: a smaller integer cannot be 5 times the larger number.
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).
the sum of two consecutive integers is -241, what is the larger integer?
5
114.As we know that the numbers are 2 consecutive even integers, we know that one number will be 2 larger than the other. We can use this to solve the problem with algebra:Where x is the smaller number,x + (x + 2) = 2262x + 2 = 2262x = 224x = 112Therefore the larger integer is 112 + 2 = 114
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
There are no such integers.
3*(x+1) - x = 7 So 3x + 3 - x = 7 then 2x = 4 or x = 2 So the two integers are 2 and 3
Suppose the smaller integer is x, then the larger one is x+1. x + 3*(x+1) = 43 That is x + 3x + 3 = 43 so that 4x = 40 and that implies that x = 10 and so the other integer is 11.