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Suppose the smaller integer is x, then the larger one is x+1.

x + 3*(x+1) = 43

That is x + 3x + 3 = 43 so that 4x = 40

and that implies that x = 10 and so the other integer is 11.

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Q: When the smaller of two consecutive integers is added to three times the larger the result is 43 find the integers?
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