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If you have height and diagonal measurement of a rectangle how do you find width?
The square of the diagonal minus the square of the height would equal the square of the width. Therefore the square root of the solution to the above problem would be the width
How do I find the diagonal measurement of a rectangle with only the height of A inches and with a width-to-height ratio of 43?
To find the diagonal measurement of a rectangle with a height of A inches and a width-to-height ratio of 43, first calculate the width (W) using the ratio: ( W = 43 \times A ). Then, use the Pythagorean theorem to find the diagonal (D): ( D = \sqrt{A^2 + W^2} = \sqrt{A^2 + (43A)^2} = \sqrt{A^2(1 + 43^2)} = A \sqrt{1 + 1849} = A \sqrt{1850} ). Thus, the diagonal measurement is ( A \sqrt{1850} ) inches.
If the height is 12 and the diagonal meausurement is 20 what is the width of the rectangle?
Width is 16.
What are the steps taken to get the diagonal measurement of a rectangle?
-- Multiply the rectangle's length by itself. ('square' the length) -- Multiply the rectangle's width by itself. ('square' the width) -- Add the two results. -- Find the square root of the sum. It is the length of the diagonal.
What is the diagonal of a 60 x 100 rectangle?
To find the diagonal of a rectangle, you can use the Pythagorean theorem. For a rectangle with a width of 60 and a height of 100, the diagonal ( d ) can be calculated using the formula ( d = \sqrt{(width^2 + height^2)} ). Thus, ( d = \sqrt{(60^2 + 100^2)} = \sqrt{3600 + 10000} = \sqrt{13600} \approx 116.62 ). Therefore, the diagonal of the rectangle is approximately 116.62 units long.
If you have height and diagonal measurement of a rectangle how do you find width?
The square of the diagonal minus the square of the height would equal the square of the width. Therefore the square root of the solution to the above problem would be the width
If the length of a rectangle is 16 and the width is 12 what is the diagonal measurement?
The diagonal is 20.
How do I find the diagonal measurement of a rectangle with only the height of A inches and with a width-to-height ratio of 43?
To find the diagonal measurement of a rectangle with a height of A inches and a width-to-height ratio of 43, first calculate the width (W) using the ratio: ( W = 43 \times A ). Then, use the Pythagorean theorem to find the diagonal (D): ( D = \sqrt{A^2 + W^2} = \sqrt{A^2 + (43A)^2} = \sqrt{A^2(1 + 43^2)} = A \sqrt{1 + 1849} = A \sqrt{1850} ). Thus, the diagonal measurement is ( A \sqrt{1850} ) inches.
If the height is 12 and the diagonal meausurement is 20 what is the width of the rectangle?
Width is 16.
What are the steps taken to get the diagonal measurement of a rectangle?
-- Multiply the rectangle's length by itself. ('square' the length) -- Multiply the rectangle's width by itself. ('square' the width) -- Add the two results. -- Find the square root of the sum. It is the length of the diagonal.
If the diagonal measurement of a rectangle is 25 cm and the width is 15 cm what is the lenght?
The length is 20 cm.
What is the diagonal of a 60 x 100 rectangle?
To find the diagonal of a rectangle, you can use the Pythagorean theorem. For a rectangle with a width of 60 and a height of 100, the diagonal ( d ) can be calculated using the formula ( d = \sqrt{(width^2 + height^2)} ). Thus, ( d = \sqrt{(60^2 + 100^2)} = \sqrt{3600 + 10000} = \sqrt{13600} \approx 116.62 ). Therefore, the diagonal of the rectangle is approximately 116.62 units long.
How do you find the width of a rectangle knowing only the length?
the width is always shorter than the length. other than that, you would require more information about the rectangle (such as the area or the diagonal measurement) to ascertain the width
What is a closed figure that has two basic units of measurement?
A rectangle. Height and width.
The diagonal of a rectangle is 50cm if the length of a rectangle is 40cm what is the width?
The width will be 30cm
What is the diagonal of a rectangle with width 10cm and length 24cm?
The diagonal is 26cm
What is the diagonal length of a rectangle with width 163Cm and height 107Cm?
Using Pythagoras' theorem it works out as 194.9820505 or 195 centimeters
