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The length is 20 cm.

Q: If the diagonal measurement of a rectangle is 25 cm and the width is 15 cm what is the lenght?

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Width is 5.

Diagonal = 10 meters.

It depends on whether you want the width as a fraction of the length or perimeter or something else - like the diagonal.

15 cm Solved through Pythagoras' theorem.

Using Pythagoras' theorem it is about 10.81665383 inches.

Related questions

The diagonal is 20.

if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units

The area of a rectangle is length times width. If you have the length and a diagonal, you will first have to figure out the width, using the formula of Pythagoras. length2 + width2 = diagonal2; solving for width: width = square root of (diagonal2 - length2). Once you have the width, just multiply lenght x width.

-- Multiply the rectangle's length by itself. ('square' the length) -- Multiply the rectangle's width by itself. ('square' the width) -- Add the two results. -- Find the square root of the sum. It is the length of the diagonal.

Area of a rectangle is width times lenght. 14m in lenght (times) 5m in width = 70m2

The square of the diagonal minus the square of the height would equal the square of the width. Therefore the square root of the solution to the above problem would be the width

the width is always shorter than the length. other than that, you would require more information about the rectangle (such as the area or the diagonal measurement) to ascertain the width

The width will be 30cm

The diagonal is 26cm

You can't tell. There are an infinite number of sets of length and width that havea diagonal of 46.The only thing we know for sure is that whatever they are, the square of the lengthand the square of the width add up to 2,116.

Width is 5.

Same as a rectangle. It is, after all, a type of rectangle (lenght >< width)